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Sphinxa [80]
3 years ago
10

Mrs. shearer complained to her doctor that she had severe pain in her chest and feared that she was having a heart attack. an el

ectrocardiogram revealed nothing unusual, but mrs. shearer insisted that every time that she took a breath she experienced pain. what might be the cause of mrs. shearer's pain?
Biology
1 answer:
Tpy6a [65]3 years ago
5 0

Based on the scenario above, since the electrocardiogram revealed nothing unusual and indicate the she’s not having a heart attack, the pain the she may be experiencing every time she took a breath is pleurisy. Pleurisy is a condition in which this occurs when the pleura or the membrane the consist of the layer of tissue that is inlined with the inner side of an individual’s chest cavity and layer of tissue that surrounds the lungs has been inflamed or swollen in which will make an individual experience symptoms such as having sharp pain in the chest and that it would usually worsen when the individual is breathing.

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FromTheMoon [43]

C. Experimental

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8 0
3 years ago
Before a captive breeding program and subsequent reintroduction of the black-footed ferret it is believed that their total popul
irga5000 [103]

Answer:

a) 99.93%

b) 99.98%

Explanation:

Given that:

Total population size was only around 18 individuals ( for  black-footed ferret)

If the annual survival rate in the wild was 0.4%.

a)

What is the probability that all 18 would have died in a single year?

To find that; we multiply the annual survival rate in the wild with the total population; which is:

(0.4%×18) = 0.072%

Then; we subtract it from a total of 100% in order to determine the probability that all 18 would have died in a single year.

= (100.00% - 0.072%)

= 99.93%

b)

What is the probability that all 18 would have died in a single year if canine distemper was present?

Given that;

Because of the presence of canine distemper disease, the annual mortality rate might have been as high as 0.89.

To determine the probability; we have:

1 - Annual mortality rate = annual survival rate

1 - 0.89 = 0.11 %

Therefore, 0.11% of 18 individuals = (0.0011 × 18)

= 0.0198%

Probability that all 18 would have died in a single year if canine distemper was present = 100 - probability of annual survival rate

= (100 - 0.0198)%

= 99.98%

7 0
3 years ago
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sattari [20]
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3 0
3 years ago
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Answer:

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