Answer:
The concentration is 4.16 grams per liter, we call the solution saturated.
Explanation:
Step 1: Data given
The solubility of calcium chromate in water is 4.16 grams per liter.
Saturated Solution : A solution with solute that dissolves until it is unable to dissolve anymore, leaving the undissolved substances at the bottom.
Unsaturated Solution: A solution (with less solute than the saturated solution) that completely dissolves, leaving no remaining substances.
Supersaturated Solution: A solution (with more solute than the saturated solution) that contains more undissolved solute than the saturated solution because of its tendency to crystallize and precipitate.
Step 2:
If the calcium chromate solution has a concentration of 4.16 grams per liter.
If the concentration is less than 4.16 grams per liter, we call it unsaturated.
If the concentration is more than 4.16 grams per liter, we call it supersaturated.
The concentration is 4.16 grams per liter, we call the solution saturated.
When propane is burned in air in a process known as combustion it produce carbon (IV) oxide and water
the word equation is as follows,
propane + oxygen--->carbon (IV) oxide + water
chemical equation is as follows
2C3H8 +7O2---> 3CO2 + 8 H2O
hence 2 moles of propane reacted with 7 moles of oxygen to give 3 moles of CO2 and 8 moles of H2o
Answer:
cells=1
organ=3
organ system=4
tissue=2
Explanation:
i just did the question right now and i got them all correct.
Answer:
21.5mL of a 0.100M HCl are required
Explanation:
The sodium phenoxide reacts with HCl to produce phenol and NaCl in a 1:1 reaction.
To solve this question we need to find the moles of sodium phenoxide. These moles = Moles of HCl required to reach equivalence point and, with the concentration, we can find the needed volume as follows:
<em>Mass NaC6H5O:</em>
1.000g * 25% = 0.250g NaC6H5O
<em>Moles NaC6H5O -116.09g/mol-</em>
0.250g NaC6H5O * (1mol/116.09g) = 2.154x10⁻³ moles = Moles of HCl required
<em>Volume 0.100M HCl:</em>
2.154x10⁻³ moles HCl * (1L/0.100mol) = 0.0215L =
<h3>21.5mL of a 0.100M HCl are required</h3>
