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Roman55 [17]
3 years ago
14

Please help with this lab !

Chemistry
1 answer:
vekshin13 years ago
4 0
To get out the iron filings put everything in to a container and then put the magnet to the side to attract them. Pull them out of the container. Then, I don’t know how to separate the sand and salt. Maybe evaporate the salt? I joke you can figure it out. Best of luck! :)
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What is the pressure of nitrogen in atmospheres of a sample that is at 745 mmHg?
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<span>The pressure of nitrogen in atmospheres of a sample that is at 745 mmHg- n2= .780 atm because 78 (from the 78%) 78/100=0.78.</span>
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3 years ago
Some chemical factories make hydrogen gas (H2) using a process called steam methane reforming. In this process, methane (CH4) co
erica [24]

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steam and methane

Explanation:

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2 years ago
Solid aluminum (AI) and oxygen (O_2) gas react to form solid aluminum oxide (Al_2O_3). Suppose you have 7.0 mol of Al and 9.0 mo
Nimfa-mama [501]

Answer:

There will be formed 3.5 moles of Al2O3 ( 356.9 grams)

Explanation:

Step 1: Data given

Numbers of Al = 7.0 mol

Numbers of mol O2 = O2

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Molar mass of O2 = 32 g/mol

Step 2: The balanced equation

4Al(s) + 3O2(g) → 2Al2O3(s)  

Step 3: Calculate limiting reactant

For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3

Al is the limiting reactant, it will be consumed completely (7 moles).

O2 is in excess.  There will react 3/4 * 7 = 5.25 moles

There will remain 9-5.25 = 3.75 moles

Step 4: Calculate moles Al2O3

For 4 moles Al we'll have 2moles Al2O3

For 7.0 moles of Al we'll have 3.5 moles of Al2O3 produced

Step 5: Calculate mass of Al2O3

Mass Al2O3 = moles Al2O3 * molar mass Al2O3

Mass Al2O3 = 3.5 moles* 101.96 g/mol

Mass Al2O3 = 356.9 grams

There will be formed 3.5 moles of Al2O3 ( 356.9 grams)

3 0
3 years ago
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6 0
3 years ago
Read 2 more answers
4+4=?
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Answer:

8

Explanation:

3 0
3 years ago
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