amount of time the two substances are in contact. area in contact between the two substances. specific heat of the material that makes up the substances. the density of the two substances in contact.
Answer:
Explanation:
Given:
V1 = 200 ml
T1 = 20 °C
= 20 + 273
= 293 K
P1 = 3 atm
P2 = 2 atm
V2 = 400 ml
Using ideal gas equation,
P1 × V1/T1 = P2 × V2/T2
T2 = (2 × 400 × 293)/200 × 3
= 234400/600
= 390.67 K
= 390.67 - 273
= 117.67 °C
Explanation:
Two acids we come into contact with in an average week
- Vinegar is an 10% solution of acetic acid
in water. Used in salad dressing and while cooking food. It has a sour taste. - Citric acid present in fruits and vegetables like : lemons, orange, tomatoes etc. It is a weak organic acid with sour taste.
Two bases we come into contact with in an average week.
- Baking soda (
) is used in baking food like: cakes, cookies, breads. Baking soda is one of the ingredient while baking breads and cakes. - Caustic soda (NaOH) is used for preparation of detergents, papers , soaps etc. We use soaps and detergents for washing.
Answer:
for the reaction is 18.05
Explanation:
Equilibrium constant in terms of partial pressure (
) for this reaction can be written as-

where
and
are equilibrium partial pressure of
and
respectively
Hence
= 18.05
So,
for the reaction is 18.05
<u>Answer:</u> The rate law expression for the given reaction is written below.
<u>Explanation:</u>
Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
For the given chemical equation:

Rate law expression for the reaction:
![\text{Rate}=k[NO]^2[H_2]^2](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5E2%5BH_2%5D%5E2)
Hence, the rate law expression for the given reaction is written above.