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3 years ago

One of mercurys spectral lines has a wavelength of 6.234x10-7 m. What is the lines frecuency?

1 answer:

8 0

Idk if there is a certain way to solve this with certain steps but if not than can't you just do the math? If it were simple math it would be 55.34 m.

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What process occurs during the corrosion of iron?

Butoxors [25]

Answer:

Explanation:

The iron corrodes so it oxidized

8 0

3 years ago

Can somebody please help me with this question, I'm very confused! I thought i did it right because i found Kb and the conc. of

andrew-mc [135]

Let's investigate the substances involved in the reaction first. The compound <span>CH3NH3+Cl- is a salt from the weak base CH3NH2 and the strong acid HCl. When this salt is hydrated with water, it will dissociate into CH3NH2Cl and H3O+:

CH3NH3+Cl- + H2O </span>⇒ CH3NH2Cl + H3O+

Nest, let's apply the ICE(Initial-Change-Equilibrium) table where x is denoted as the number of moles used up in the reaction:

CH3NH3+Cl- + H2O ⇒ CH3NH2Cl + H3O+
Initial 0.51 0 0
Change -x +x +x
-------------------------------------------------------------------------------
Equilibrium 0.51 - x x x

Then, let's find the equilibrium constant of the reaction. Since the reaction is hydrolysis we use KH, which is the ratio of Kw to Ka or Kb. Kw is the equilibrium constant for water hydrolysis which is equal to 1×10⁻¹⁴. Since the salt comes from the weak base, we use Kb. Since pKb = 3.44, then. 3.44 = -log(Kb). Thus, Kb = 3.6307×10⁻⁴

KH = Kw/Kb = (x)(x)/(0.51 - x)
1×10⁻¹⁴/ 3.6307×10⁻⁴ = x²/(0.51-x)
x = 3.748×10⁻⁶

Since x from the ICE table is equal to the equilibrium concentration of H+, we can find the pH of the aqueous solution:

pH = -log(H+) = -log(x)
pH = -log ( 3.748×10⁻⁶)
pH = 5.43

6 0

3 years ago

What is the volume of gas at 2.00atm and 200.0K if its original volume was 300.0L at 0.25atm and 400.OK?

adell [148]

C because the volume of gas at 2.000 atm is 9.38L original volume was 3000l

5 0

3 years ago

Nuclei with the same mass number but different atomic numbers are called isobars. Consider Ca-40, Ca-41, K-41 and Ar-41. (a) Whi

SVETLANKA909090 [29]

Answer:

Part a:

Isobars: Ca-41, K-41 and Ar-41

Part b:

Number of proton

Part c:

Incorrect statement

Explanation:

Part a:

Nuclei with same mass number are called isobars.

Given:

Ca-40, Ca-41, K-41 and Ar-41

Ca-41, K-41 and Ar-41 have equal mass numbers, so these are isobars.

Part b:

Atomic number of Ca = 20

Atomic no. = Number of proton.

So, Ca-40 ans C-41 have same number of proton or in other words proton count is common in both.

Part c:

Number of neutrons in Ca-41

Atomic number = 20

Mass number = 41

Number of neutron = Mass number -atomic number

= 41 -20 = 21

Number of neutrons in K-41

Atomic number = 19

Mass number = 41

Number of neutron = Mass number -atomic number

= 41 -19 = 22

Number of neutrons in Ar-41

Atomic number = 18

Mass number = 41

Number of neutron = Mass number -atomic number

= 41 -18 = 23

So, the statement is incorrect.

3 0

3 years ago

Can you help me with number 29 ?

Anton [14]

Answer:

Electronegativities generally increase from left to right across a period

Therefore the answer is B.

4 0

2 years ago