The reaction is,
H2S + I2 --------------> 2 HI +S
Molar weight of H2S = 34 g per mol
Molar weight of HI =128 g per mol
Molar weight of I2 =254 g per mol
Moles of H2S in 49.2 g = 49.2 /34 mol = 1.447 mol
So according to stoichiometry of the reaction, number of I2 mols needed
= 1.447 mol
The mass of I2 needed = 1.447 mol x 254 g
Answer:
The answer to your question is: 0.3 moles of AgNO₃
Explanation:
1.0 L sample
0.1 mol of NaCl
0.1 mol of CaCl₂
AgNO₃ = ? moles
Reactions
NaCl + AgNO₃ ⇒ AgCl + NaNO₃
Then 1 NaCl mol --------------- 1 AgNO₃
0.1 mol -------------- x
x = 0.1 moles of AgNO₃ needed
CaCl₂ + 2 AgNO₃ ⇒ 2 AgCl + Ca(NO₃)₂
Then 1 mol of CaCl₂ ------------- 2 moles of AgNO₃
0.1 mol ------------- x
x = 0.2 moles of AgNO₃
Total moles of AgNO₃ = 0.1 + 0.2 = 0.3
The molarity of a solution is the number of moles of a substance per liter of the solution.
400 mL becomes 0.400 liters
You have 0.0345 moles of ammonium chloride NH4Cl, so take the number of moles over the number of liters to find the answer.
0.0345 moles/0.400 liters = 0.0863 moles/liter
0.0863M = molarity of the solution
The enthalpy change for the reaction 2K + S + K2S using the following thermochemical reactions is mathematically given as
dn=70.7kg
<h3>What is the enthalpy change for the reaction?</h3>
Generally, the equation for the Chemical reaction is mathematically given as
2k+s----->K2S
Therefore
KS+K----->K2S
Therefore
dn=dn1+dn2
dn=32.5+38.2
dn=70.7kg
In conclusion, the enthalpy change is
dn=70.7kg
Read more about Chemical reaction
brainly.com/question/16416932
#SPJ1
Answer:
its average per average is 0.5
Explanation:
when 2 average is 1 and 1 average is0.5
