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Tatiana [17]
3 years ago
13

In a certain triangle, one angle has a measure of 30° and another angle has a measure of 120°. If the triangle is isosceles, the

n which of the following could be the measure of the third angle?
A. 120°
B. 60°
C. 30°
D. 75°
Mathematics
1 answer:
Aloiza [94]3 years ago
3 0

The answer is C because an isosceles triangle got up to 180 degrees and 120 + 30 is 150 and 150 + 30 is 180 so therefore your answer is C

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The translation of ABCD to A’B’C’D’ is given by (x+?, y-?)
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Answer:

The translation of ABCD to A’B’C’D’ is given by (x+2, y-4)

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What is 697*100 please help
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Here is a trick I always use:

Get rid of both zeros in100 for now 
So just do 697*1 which is just 697

Now add the two zeros to your answer to get 69,700 which is the final answer
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Answer:i'm a bit confused

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For the inequality 4x2>y−3, where is the graph shaded and is the curve solid or dotted?
Alja [10]

Answer:

Dotted Curve

Shaded Area includes the Origin.

Step-by-step explanation:

I am assuming that you mean 4x² > y-3.

Since the inequality sign is greater than, the line would be dotted. The curve would be solid if the inequality was an 'X or equal to' sign.

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4(0)² > 0 - 3

0 > -3

Since the given statement is true, the origin is a solution and we would shade below the curve.

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See the graph attached.

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8 0
2 years ago
5. Draw 2 line segment of different lengths that both have M as a midpoint.
Alona [7]

Step 1: Write out the coordinate of the midpoint

M(-2,-3)

Step 2: Find the coordinates of the two line segments by testing for values that will yeild the midpoint coordinates

\begin{gathered} \text{ Since the midpoint M is at (-2,-3), then} \\ M(-2,-3)\Rightarrow(x_m,y_m) \\ x_m=\frac{x_1+x_2}{2}=-2 \\ y_m=\frac{y_1+y_2}{2}=-3 \end{gathered}\begin{gathered} \text{Thus,} \\ x_1+x_2=-2(2)=-4 \\ y_1+y_2=-3(2)=-6 \end{gathered}

From the above, we can deduce to four values that will give -4 for the x-values and -6 for the y-values.

\begin{gathered} \text{For the first line segment},\text{ say line AB} \\ x_1+x_2=-6+2=-4,x_1=-6,x_2=2 \\ y_1+y_2=-9+3=-6,y_1=-9,y_2=3 \\ \text{Therefore, line AB coordinate is } \\ A(-6,-9),B(2,3) \end{gathered}\begin{gathered} \text{For the first line segment},\text{ say line CD} \\ x_1+x_2=-10+6=-4,x_1=-10,x_2=6 \\ y_1+y_2=-14+8=-6,y_1=-14,y_2=8 \\ \text{Therefore, line AB coordinate is } \\ C(-10,-14),D(6,8) \end{gathered}

Step 3: Draw the two lines segment on a cartesian plane showing M as the common midpoint.

6 0
1 year ago
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