Answer:

Step-by-step explanation:
An equation of a line is given
, where m is the gradient or 
The rise indicates the change in value of y (vertical change in the graph).
The run indicates the change in value of x (horizontal change in the graph).
Let point 1 of the graph be (x,y) = (0,-34) and point 2 be (x,y) = (20,0).
Substitute point 1 into the graph to get the constant c.



∴ The equation of the line is, 
9514 1404 393
Answer:
Step-by-step explanation:
Let a and s represent the prices of adult and student tickets, respectively.
13a +12s = 211 . . . . . . ticket sales the first day
5a +3s = 65 . . . . . . . ticket sales the second day
Subtracting the first equation from 4 times the second gives ...
4(5a +3s) -(13a +12s) = 4(65) -(211)
7a = 49 . . . . . . . simplify
a = 7 . . . . . . . divide by 7
5(7) +3s = 65 . . . . substitute into the second equation
3s = 30 . . . . . . . subtract 35
s = 10 . . . . . . . divide by 3
The price of one adult ticket is $7; the price of one student ticket is $10.
Answer:
pi r squared divided by 2 for the half circle then add the area of the box to you number and there is your area
Answer: 6.4b - 32
Step-by-step explanation:
The answer is:
212/100
=(200/100)+(12/100)
=2.00+0.12
=2.12