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3 years ago

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X-2y=7; ( ,2) (,1) complete each ordered pair so that is a solution of the given linear equation.

2 answers:

marshall27 [118]3 years ago

8 0

To complete each ordered pair, you would have to substitute the 1 and 2 in for y. Let's start with the 2 first. X-2(2)=7, x-4=7. Add 4 on each side. X=11. First ordered pair is (11,2). Now do the 1. X-2(1)=7, x-2=7. Add 2 on both sides. Second ordered pair is (9,1). Answers are (11,2) and (9,1)

VikaD [51]3 years ago

8 0

Answers are (11,2) and (9,1)

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Marianna [84]

Answer:

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Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let $(x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)$

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

⇒ $d=\sqrt{(2-5)^2+(4-3)^2}$

⇒ $d=\sqrt{9+1}$

⇒ $d=\sqrt{10}$ ....(1)

Now, we find the length of M'K'

let $(x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)$

$d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}$

⇒ $d^{'}=\sqrt{(-2+5)^2+(3-4)^2}$

⇒ $d^{'}=\sqrt{9+1}$

⇒ $d^{'}=\sqrt{10}$ .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct

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