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vfiekz [6]
3 years ago
6

Find the TRUE statement. Use the underlined word to determine whether the statement is true or false. Question 3 options: Electr

omagnetic waves are mechanical because they require a medium to travel. Electromagnetic waves are transverse because they have electric and magnetic fields that move perpendicular to the direction of energy transfer. The speed of an electromagnetic wave depends on the frequency of the wave. Gamma rays are faster than radio waves. As the frequency of an EM wave increases, so does the wavelength. They are directly related.
Physics
1 answer:
dolphi86 [110]3 years ago
3 0
<h2> Electromagnetic waves are transverse because they have electric and magnetic fields that move perpendicular to the direction of energy transfer.</h2>

(sorry if I'm wrong) :(

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Our sun is quite average when looking at all the stars in the Universe. There are stars that are smaller, like Wolf359, and there are also larger stars, like Betelgeuse. Our sun is essentially right in the middle of the star-size spectrum. 

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When light is incident on a boundary between two mediums, it often slows
mina [271]

Answer:

the answer is

D.refraction

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How long would it take a leopard, running at an average speed of 20 m/s to travel 500 m?
alexandr1967 [171]

Answer:

25 seconds

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3 years ago
You hold a ruler that has a charge on its tip 6 cm above a small piece of tissue paper to see if it can be picked up. The ruler
Fed [463]

Answer:

9.81 × 10⁻¹⁰ C

Explanation:

Given:

Distance between the tissue and the tip of the scale, r = 6 cm = 0.06 m

Charge on the ruler, Q = - 12 μC = - 12 × 10⁻⁶ C

Mass of the tissue = 3 g = 0.003 Kg

Now,

The force required to pick the tissue, F = mg

where, g is the acceleration due to gravity

also,

The force between (F) the charges is given as:

F=\frac{kQq}{r^2}

where,

q is the charge on the tissue

k is the Coulomb's constant = 9 × 10⁹ Nm²/C²

thus,

mg=\frac{kQq}{r^2}

on substituting the respective values, we get

0.003\times9.81=\frac{9\times10^9\times(-12\times10^{-6})\times q}{0.06^2}

or

q = 9.81 × 10⁻¹⁰ C

Minimum charge required to pick the tissue paper is 9.81 × 10⁻¹⁰ C

3 0
3 years ago
What is the electric field at a location b → = &lt;-0.5, -0.4, 0&gt; m, due to a particle with charge +2 nC located at the origi
Naddika [18.5K]

Answer:

E = \frac{8.99 x10^{9} \frac{Nm^2}{C^2} * 2x10^{-9} C}{(0.64m)^2} =43.85N

Explanation:

For this case we assume that we want to find the electrical field at the point P as we can see on the figure attached.

The electrical field wormula is given by:

E = \frac{K Q}{d^2}

Where r is the distance from the point and the charge. On this case we can use the Pythagoras theorem and we got:

d^2 = (-0.5m)^2 +(-0.4)^2 = 0.41m^2

d =\sqrt{0.41}= 0.64m

And now we can replace into the formula since we know that Q = 2nC= 2x10^{-9}C and K = 8.99 x10^{9} \frac{Nm^2}{C^2}, and we got:

E = \frac{8.99 x10^{9} \frac{Nm^2}{C^2} * 2x10^{-9} C}{(0.64m)^2} =43.85N

4 0
3 years ago
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