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DerKrebs [107]
3 years ago
15

D%20" id="TexFormula1" title="what \: is \: refraction \: of \: light \: {?} " alt="what \: is \: refraction \: of \: light \: {?} " align="absmiddle" class="latex-formula">
​
Physics
2 answers:
topjm [15]3 years ago
8 0

When light passes through one transparent medium to another transperent medium it bends and that beding of light is know as refraction of light !

Radda [10]3 years ago
5 0
Refraction of light is the bending of light as it passes from one medium to another.
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No, momentum is conserved so:
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it is C. 100 kg m/s
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the train is travelling at 15 m/s. It accelerates at 3 m/s² for 20 seconds. How far does the train travel in this time?
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Air enters a nozzle steadily at 2.21 kg/m3 and 20 m/s and leaves at 0.762 kg/m3 and 150 m/s. If the inlet area of the nozzle is
saveliy_v [14]

Answer:

a) The mass flow rate through the nozzle is 0.27 kg/s.

b) The exit area of the nozzle is 23.6 cm².

Explanation:

a) The mass flow rate through the nozzle can be calculated with the following equation:

\dot{m_{i}} = \rho_{i} v_{i}A_{i}

Where:

v_{i}: is the initial velocity = 20 m/s

A_{i}: is the inlet area of the nozzle = 60 cm²  

\rho_{i}: is the density of entrance = 2.21 kg/m³

\dot{m} = \rho_{i} v_{i}A_{i} = 2.21 \frac{kg}{m^{3}}*20 \frac{m}{s}*60 cm^{2}*\frac{1 m^{2}}{(100 cm)^{2}} = 0.27 kg/s  

Hence, the mass flow rate through the nozzle is 0.27 kg/s.

b) The exit area of the nozzle can be found with the Continuity equation:

\rho_{i} v_{i}A_{i} = \rho_{f} v_{f}A_{f}

0.27 kg/s = 0.762 kg/m^{3}*150 m/s*A_{f}

A_{f} = \frac{0.27 kg/s}{0.762 kg/m^{3}*150 m/s} = 0.00236 m^{2}*\frac{(100 cm)^{2}}{1 m^{2}} = 23.6 cm^{2}

Therefore, the exit area of the nozzle is 23.6 cm².

I hope it helps you!                                                                  

5 0
3 years ago
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lora16 [44]

d)through a railroad track

7 0
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A 35 N force makes a 10 degree angle with the positive x-axis. What is the magnitude of the vertical component of the force?
Snowcat [4.5K]

Answer:

6.07 N

Explanation:

Given that,

Force, F = 35 N

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We need to find the magnitude of the vertical component of the force. It can be given by :

F_y=F\sin\theta\\\\=35\times \sin(10)\\\\=6.07\ N

So, the magnitude of the vertical component of the force is 6.07 N.

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3 years ago
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