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astra-53 [7]
3 years ago
10

To hang lights up on his house.Garrett place is a 14 foot ladder 4 feet from the base of the house. How high up the house will t

he ladder reach
Mathematics
2 answers:
nydimaria [60]3 years ago
6 0

Answer: 13.42 feet

Step-by-step explanation:

Given : To hang lights up on his house.Garrett place is a 14 foot ladder 4 feet from the base of the house.

Since house is standing vertical to to ground making a right angles , so the triangle made by ladder must be a right triangle, where ladder is a hypotenuse.

Let h be the height of the house where the ladder reach.

By Pythagoras Theorem , we have

x^2+4^2=14^2\\\\\Rightarrow\ x^2+16=196\\\\\Rightarrow\ x^2=196-16\\\\\Rightarrow\ x^2 =180\\\\\Rightarrow\ x=\sqrt{180}=13.416407865\approx13.42\text{ feet}

Hence, the height of the house where the ladder reach= 13.42 feet

Firlakuza [10]3 years ago
5 0

This seems like a right triangle problem.

So assuming 14 feet is the hypotenuse and 4 feet is a leg of the right triangle, we can use the pythagorean theorem (a^{2} +b^{2} =c^{2}) to solve for the height of the house, in which we shall name it x.

So, the equation is 4^{2} +x^{2} =14^{2}.

Solve for x:

16+x^{2}= 196

x^{2}= 196-16

x^{2}= 180

x = 6√5 feet


Hope this helps!

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