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3 years ago

What is the y-value when x equals - 12?

Mathematics

1 answer:

kirill115 [55]3 years ago

7 0

Answer:

I think the answer is -140

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Will give brainliest please help ASAP

Snezhnost [94]

Answer:

Step-by-step explanation:

y>-3x+1 Negative slope

y<x+2 Positive slope

< or > have dotted line

< or > have a solid line

> or > means solutions are above the line

< or < means solutions are below the line

The one with negative slope has a dotted line and solutions above it.

The one with positive slope has a solid line and solutions below it.

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4 years ago

There is a loss of Rs 5 when a watch is sold at the discount of 10%. IF the watch is sold at the discount of 5%, there is profit

Colt1911 [192]

At disc of 10% there was 5rupees loss and at disc of 5 % dis there was 22.5 profit
so 5% *x= 22.5+5=27.5
x=27.5 *20
x=550

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3 years ago

Which expression is shown on the number line?

notsponge [240]

Answer: i think its e

Step-by-step explanation:......

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3 years ago

Read 2 more answers

An artist used silver wire to make a square that has a perimeter of 40 inches. She then used copper wire to make the largest cir

JulijaS [17]

The area of the copper circle A= 69.08 $inches^{2}$ .

Step-by-step explanation:

Given data,

Perimeter of the Square =40 inches.

Let us find the measurement of one side.

The formula for perimeter of a square is 4a.

where a is length of one side of a square.

We know that perimeter of the square is 40.

∴ 4a=40.

a=10 inches.

Imagine that moving one side of the square into the circle.

You can observe that length of one side of square is the diameter of the circle.

∴Diameter of the circle =10 inches.

⇒ Radius of the circle r= 5 inches.

Area of the circle A= π $r^{2}$ .

A= 3.14×5×5.

Area of the circle A= 69.08 $inches^{2}$ .

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4 years ago

For the given functions, (a) express dw/dt as a function of t, both by using the chain rule and by expressing w in terms of t an

ch4aika [34]

By the chain rule,

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}$

We have

$w=7ye^x-\ln z\implies\begin{cases}\dfrac{\partial w}{\partial x}=7ye^x\\\\\dfrac{\partial w}{\partial y}=7e^x\\\\\dfrac{\partial w}{\partial z}=-\dfrac1z\end{cases}$

and

$\begin{cases}x=\ln(t^2+1)\\y=\tan^{-1}t\\z=e^t\end{cases}\implies\begin{cases}\dfrac{\mathrm dx}{\mathrm dt}=\dfrac{2t}{t^2+1}\\\\\dfrac{\mathrm dy}{\mathrm dt}=\dfrac1{t^2+1}\\\\\dfrac{\mathrm dz}{\mathrm dt}=e^t\end{cases}$