Three consecutive even integers have a sum of -48. Find the largest integer.
1 answer:
Answer:
<h3>
- 14</h3>
Step-by-step explanation:
{x - some integer}
2x - the first even integer
2x+2 - the second consecutive even integer
2x+4 - the third consecutive even integer (the largest)
2x + 2x+2 + 2x+4 - the sum of three consecutive even integers
2x + 2x+2 + 2x+4 = -48
6x + 6 = -48
÷3 ÷3
2x + 2 = -16
+2 +2
2x+4 = -14
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||u|| = sqrt(5² + (-12)²)
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