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3 years ago

Three consecutive even integers have a sum of -48. Find the largest integer.

Mathematics

1 answer:

kobusy [5.1K]3 years ago

6 0

Answer:

Step-by-step explanation:

{x - some integer}

2x - the first even integer

2x+2 - the second consecutive even integer

2x+4 - the third consecutive even integer (the largest)

2x + 2x+2 + 2x+4 - the sum of three consecutive even integers

2x + 2x+2 + 2x+4 = -48

6x + 6 = -48

÷3 ÷3

2x + 2 = -16

+2 +2

2x+4 = -14

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What's the answer for this problem number 6 and how did you get your answer?

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$\frac{7}{b + 5} = \frac{10}{5} \\$

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Multiply the sides of the equation by ( b + 5 ) :

$7 =2 \times (b + 5)$

$7 = 2b + 10$

Subtract the sides of the equation minus 10 :

$7 - 10 = 2b$

$- 3 = 2b$

Divided the sides of the equation by 2 :

$b = - \frac{3}{2} \\$

____________________________

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Answer:

Step-by-step explanation:

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