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REY [17]
3 years ago
9

What is the range of f(x)= -2x+5 with domain {1,2,3,4}?

Mathematics
1 answer:
Karolina [17]3 years ago
7 0
Range is any number besides 1,2,3,4

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Me. Watson is making 34.6 fluid once's of red paint and 18.6 fluid ounces of yellow paint to make orange paint. How many 3.5- fl
forsale [732]

Answer: She can fill about 15 3.5- fluid once jars.

Step-by-step explanation:

Given:

Quantity of red paint = 34.6 fluid ounces

Quantity of yellow paint = 18.6 fluid ounces

Total quantity of orange color = (Quantity of red paint )+(Quantity of yellow paint )

= (34.6+18.6) fluid ounces

= 53.2 fluid ounces

Number of 3.5- fluid ounce jars she can fill = (Total quantity of orange color) ÷ 3.5

= 53.2÷3.5 = 15 (approx)

Hence, She can fill about 15 3.5- fluid once jars.

7 0
3 years ago
Would someone mind helping me? 20 points for a great and correct answer!<br> Thank you!
maria [59]
88!!! thank you i belive that is it
5 0
3 years ago
Read 2 more answers
Please help me please it’s this question
Lera25 [3.4K]
Subtract 124 and 18
7 0
3 years ago
Based on the data given in the picture, calculate the area of the car track...
Verizon [17]

Refer to the diagram below. We need to find the areas of the green and blue regions, then subtract to get the area of the orange track only.

The larger green region is composed of a rectangle of dimensions 200 meters by 4+42+4 = 50 meters, along with two semicircles that combine to make a full circle. This circle has radius 25 meters.

The green rectangle has area 200*50 = 10000 square meters. The green semicircles combine to form an area of pi*r^2 = pi*25^2 = 625pi square meters. In total, the full green area is 10000+625pi square meters. I'm leaving things in terms of pi for now. The approximation will come later.

The blue area is the same story, but smaller dimensions. The blue rectangle has dimensions 200 meters by 42 meters, so its area is 200*42 = 8400 square meters. The blue semicircular pieces combine to a circle with area pi*r^2 = pi*21^2 = 441pi square meters. In total, the blue region has area 8400+441pi square meters.

After we figure out the green and blue areas, we subtract to get the orange region's area, which is the area of the track only.

orange area = (green) - (blue)

track area = (10000+625pi) - (8400+441pi)

track area = 10000+625pi - 8400-441pi

track area = (10000-8400) + (625pi - 441pi)

track area = 184pi + 1600 is the exact area in terms of pi

track area = 2178.05304826052 is the approximate area when you use the pi constant built into your calculator. If you use pi = 3.14 instead, then you'll get 2177.76 as the approximate answer. I think its better to use the more accurate version of pi. Of course, be sure to listen/follow your teachers instructions.

4 0
3 years ago
A true/false test has 40 questions. Suppose a passing grade is 30 or more correct answers. Test the claim that a student knows m
Angelina_Jolie [31]

Answer:

z≈3.16

p≈0.001

we reject the null hypothesis and conclude that the student knows more than half of the answers and is not just guessing in 0.05 significance level.

Step-by-step explanation:

As a result of step 2, we can assume normal distribution for the null hypothesis

<em>step 3:</em>

z statistic is computed as follows:

z=\frac{X-M}{\frac{\sqrt{p*(1-p)} }{\sqrt{N} } } where

  • X is the proportion of correct answers in the test (\frac{30}{40})
  • M is the expected proportion of correct answers according to the null hypothesis (0.5)
  • p is the probability of correct answer (0.5)
  • N is the total number of questions in the test (40)

z=\frac{0.75-0.50}{\frac{\sqrt{0.5*(0.5)} }{\sqrt{40} } } ≈ 3.16

And corresponding p value for the z-statistic is p≈0.001.

Since p<0.05, we reject the null hypothesis and conclude that the student knows more than half of the answers and is not just guessing in 0.05 significance level.

7 0
3 years ago
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