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weqwewe [10]
2 years ago
14

How to find the area of a capital 'L' shaped shape?

Mathematics
1 answer:
DENIUS [597]2 years ago
8 0
You split the L into 2 parts, solve the area of the 2 parts, then add the areas together.
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What is 5+1 please hurry
AfilCa [17]

Answer: 6

Step-by-step explanation:

3 0
2 years ago
What is the value of x<br> What is the value of the exterior angle
Oduvanchick [21]

Answer:

???????

Step-by-step explanation:

triangles add to 180 degrees

lets call the unknown angle y

82 + x + y = 180

we also know that y + (2x-20 ) = 180  because it is a straight line

lets solve this for y

y + (2x-20 ) = 180

subtract (2x-20) from each side

y = 180 - (2x-20)

y = 180 - 2x + 20

y = 200 -2x

substitute this in the triangle equation

82 + x + y = 180

82 + x + 200 -2x = 180

combine like terms

282 -x = 180

subtract 282 from each side

-x = -102

multiply by -1 on each side

x = 102

the exterior angle is 2x-20

exterior angle is 2(102) -20

exterior angle is 204-20

exterior angle is 184

This is impossible.


There is a mistake with this problem

The triangle is not a triangle.  Angle y would be negative. y=-4

6 0
2 years ago
Help me I'm giving 20 points <br><br>a²•b⁶ if a =½ and b=2 ?​
exis [7]

Answer:

try 0.5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If sinA =3/5 and A+B =90 find cosB
-Dominant- [34]

A+B=90^o\to B=90^o-A\\\\\cos B=\cos(90^o-A)=\cos90^o\cos A+\sin90^o\sin A\\\\=\cos A+1\cdot\dfrac{3}{5}=0+\dfrac{3}{5}=\dfrac{3}{5}\\\\\boxed{\cos B=\dfrac{3}{5}}

Used:\\\\\cos(x+y)=\cos x\cos y+\sin x\sin y\\\\\cos90^o=0,\ sin90^o=1

Other method:

Look at the picture.

\sin\theta=\dfrac{opposite}{hypotenuse}\\\\\sin A=\dfrac{3}{5}\to opposite=3\ and\ hypotenuse=5

\cos\theta=\dfrac{adjacent}{hypotenuse}\\\\adjacent=3\ and\ hypotenuse=5\to\cos B=\dfrac{3}{5}

8 0
3 years ago
Answers? Or a hint please I’m begging
olga2289 [7]
Hmm I would say x=q
Hope this helps u <3
6 0
2 years ago
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