X + x+1 + x + 2 = 20
3x + 3 = 20
3x = 17 but can't start with x = 6 because 6+7+8 > 20,
so have start with 5 + 6 + 7 = 18 are the 3 sides.
Answer:
7
Step-by-step explanation:
We want to find the number 4-digit of positive integers n such that removing the thousands digit divides the number by 9.
__
Let the thousands digit be 'd'. Then we want to find the integer solutions to ...
n -1000d = n/9
n -n/9 = 1000d . . . . . . add 1000d -n/9
8n = 9000d . . . . . . . . multiply by 9
n = 1125d . . . . . . . . . divide by 8
The values of d that will give a suitable 4-digit value of n are 1 through 7.
When d=8, n is 9000. Removing the 9 gives 0, not 1000.
When d=9, n is 10125, not a 4-digit number.
There are 7 4-digit numbers such that removing the thousands digit gives 1/9 of the number.
Answer:
2
Step-by-step explanation:
Answer:
x = 5
Step-by-step explanation:
x + 14 = 19
x + 14 - 14 = 19 - 14
x = 5
Answer:
A
B
C
Step-by-step explanation:
Well the sides of the smaller squares have to be greater than the biggest when put together.
a + b > c
So we need to find the square root of 55.

≅ <u>7.4</u>
<u />
Now for option A)
srt ⇒ 12 ≅3.5
srt ⇒ 43 ≅ 6.6
3.5 + 6.6 = <u>10.1</u>
So option A is correct.
Option B)
srt ⇒ 14 ≅ 3.7
srt ⇒ 40 ≅ 6.3
3.7 + 6.3 = <u>10</u>
So option B is also correct.
Option C)
srt ⇒ 16 = 4
srt ⇒ 37 ≅ 6.1
4 + 6.1 = <u>10.1</u>
So option C is also correct.
<em>Therefore,</em>
<em>all options are correct.</em>
<em />
<em>Hope this helps :)</em>