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3 years ago

5

Please help, i need to graduate

1 answer:

larisa86 [58]3 years ago

3 0

Answer:

i think its a or b .

not really sure, sorry

Step-by-step explanation:

You might be interested in

Please help!!!! I need this answer fast

Phantasy [73]

Answer:

sin S = 20/ 25

cos S = 15 / 20

tan S = 20/15

8 0

3 years ago

Help please it’s needed

julia-pushkina [17]

Answer:

The reasonings I provided are just examples (they are true, though!). Hope this helps!

3 0

3 years ago

If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by y = 56t − 1.86t2.

Zina [86]

Answer: (a) (i)50.42 m/s (ii) 51.35 m/s (iii) 52.094 m/s (iv) 52.2614 m/s (v) 52.27814 m/s

(b) 54.14 m/s

Step-by-step explanation:

The average speed over the given time interval [a,b]: = $\frac{y(b)-y(a)}{b-a}$

Given: If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by $y = 56t − 1.86t^2.$

(a)

(i) average speed = $\frac{y(2)-y(1)}{2-1}$

$=\frac{56(2)-1.86(2)^2-(56(1)-1.86(1)^2)}{1}$

$=50.42$ m/s

(ii) average speed = $\frac{y(1.5)-y(1)}{1.5-1}$

$=\frac{56(1.5)-1.86(1.5)^2-(56(1)-1.86(1)^2)}{0.5}$

$=51.35$ m/s

(iii) average speed = $\frac{y(1.1)-y(1)}{1.1-1}$

$=\frac{56(1.1)-1.86(1.1)^2-(56(1)-1.86(1)^2)}{0.1}$

$=52.094$ m/s

(iv) average speed = $\frac{y(1.01)-y(1)}{1.01-01}$

$=\frac{56(1.01)-1.86(1.01)^2-(56(1)-1.86(1)^2)}{0.01}$

$=52.2614
$ m/s

(v) average speed = $\frac{y(1.001)-y(1)}{1.001-01}$

$=\frac{56(1.001)-1.86(1.001)^2-(56(1)-1.86(1)^2)}{0.001}$

$=52.27814
$ m/s

(b) $y(1)=56(1)-1.86(1)^2$

$=56-1.86$

$= 54.14$ m/s

3 0

3 years ago

Which of the following exponential equations is equivalent to the logarithmic

Mars2501 [29]

B should be your answer

7 0

3 years ago

Steven ran for class president against Mandy. Steven Recieved 5 votes for every 3 votes that Mandy Recieved. Mandy Recieved 420

ki77a [65]

Answer:

700

Step-by-step explanation:

420×5=2100

2100÷3=700

Answer: 700

7 0

3 years ago