Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k
Answer: 16
Step-by-step explanation:
if we were to list all the factors of 64 and 144
64= 1,2,4,8,8,16,32,64
144= 1,2,3,4,6,8,9,12,12,16,18,24,36,48,72,144
therefore the GCF of 64 and 144 is 16
Answer:
Fv = 79.63 lb
The total upward force Fv is 79.63 lb
Step-by-step explanation:
We need to determine the total upward force, the y component of force;
Given;
Force F1 = 60.5 lb, 82.4° above horizontal
Force F2 = 37.2 lb, (82.4-50.5)° above horizontal
The vertical component of Force F1 and F2 is;
Fv = 60.5sin(82.4) + 37.2sin(82.4-50.5)
Fv = 79.63 lb
The total upward force Fv is 79.63 lb
Let y be train 1 and x train 2
y= 60mph+x
8-4 = 4 hours
((60+x)+x)4=(x+2)
(60+2x)4=(x+2)
