the line segment from a vertex to the midpoint of the opposite side. It is also an angle bisector when the vertex is an angle in an equilateral triangle or the non-congruent angle of an isoceles triangle.

7 0

2 years ago

What is 127 to the nearest 10

finlep [7]

Answer:The answer is 130

Step-by-step explanation:

3 0

2 years ago

Find the coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1)

Flauer [41]

Answer:

The coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1) are $\mathbf{(13,\frac{-9}{2})}$

Step-by-step explanation:

We need to find the coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1)

The midpoint of line segment can be found using formula:

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

We have $x_1=14, y_1=-8, x_2=12, y_2=-1$

Putting values and finding midpoint

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\Midpoint=(\frac{14+12}{2},\frac{-8-1}{2})\\Midpoint=(\frac{26}{2},\frac{-9}{2})\\Midpoint=(13,\frac{-9}{2})$

So, the coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1) are $\mathbf{(13,\frac{-9}{2})}$

4 0

3 years ago