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lakkis [162]
4 years ago
5

In 1955 an antique car that originally cost $3,668 is valued today at $62,125 if in excellent condition, which is 1 3/4 times as

much as a car in very nice condition, if you can find an owner willing to part with one for any price.What would be the value of the car in very nice condition?
Mathematics
1 answer:
chubhunter [2.5K]4 years ago
4 0

Answer:

The value of the car in very nice condition will be $35500.

Step-by-step explanation:

Let the value of car in a very nice condition be = x

The value $62125 is 1\frac{3}{4} or \frac{7}{4} or 1.75 times of x.

Now, we can calculate for x:

1.75x=62125

x=\frac{62125}{1.75}

x = 35500

Hence, the value of the car in very nice condition will be $35500.

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Step-by-step explanation:

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3 years ago
The numbers of pencils in joes backpack is 5 more than the number of pencils in sara's backpack.if joe has 8 pencils in his back
Basile [38]
The answer would be 3 more

7 0
4 years ago
Y=x-4 y=4x+2<br> whats the solution of system equations
Fittoniya [83]

Answer:

X=-2

Y=-6

Step-by-step explanation:

Since both equations are already expressed in the simplest form of y, then we equate them to be equal hence

x-4=4x+2

Bringing like terms together

-4-2=4x-x

Solving both sides

-6=3x

Making x the subject then

X=-6/3=-2

Subsrituting the value of x into any of the initial equations

Y=x-4 then y=-2-4=-6

Therefore, the solution is

X=-2

Y=-6

6 0
3 years ago
What is the equation (simplified) the inverse of y=2x^2?
Yuki888 [10]
2x^2=y\ \ \ |divide\ both\ sides\ by\ 2\\\\x^2=\dfrac{y}{2}\\\\\boxed{x=\sqrt{\frac{y}{2}}}\\\\x=\dfrac{\sqrt{y}}{\sqrt2}=\dfrac{\sqrt{y}\cdot\sqrt2}{\sqrt2\cdot\sqrt2}\to\boxed{x=\dfrac{\sqrt{2y}}{2}}\\\\\\\boxed{f(x)=2x^2\to f^{-1}(x)=\dfrac{\sqrt{2y}}{2}}
3 0
3 years ago
Derive the equation of the parabola with a focus at (−5, −5) and a directrix of y = 7
WARRIOR [948]

Answer: The equation of the parabola is (x+5)^2=-24(y-1).

Explanation:

It is given that the focus of the parabola is (-5,-5) and the directrix is y=7.

The standard form of the parabola is,

(x-h)^2=4p(y-k)

Where y=k-p is directrix and (h,k+p) is the focus.

Since focus is given,

(h,k+p)=(-5,-5)

On comparing,

h=-5

k+p=-5      .... (1)

The directrix is y=7.

k+p=7       .... (2)

Add equation (1) and (2),

2k=2

k=1

Put this value in (1).

p=-6

Put p= -6, h= -5 and k=1 in the standard form of the parabola.

(x+5)^2=4(-6)(y-1)

(x+5)^2=-24(y-1)

Therefore, the equation of parabola is (x+5)^2=-24(y-1).

8 0
3 years ago
Read 2 more answers
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