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iVinArrow [24]
3 years ago
8

Need to learn how to do beginner's algebra

Mathematics
2 answers:
maks197457 [2]3 years ago
8 0
I am doing this for points so i can catch up to my brother who is an expert

Aleonysh [2.5K]3 years ago
3 0
Just replace the number with letters. Alegbra is mainly about working with what you've already got, meaning it involves a lot of subtracting. Want me to go in more detail? Give me a thanks on this answer.
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Will give many points! PLEASE HELP!
nataly862011 [7]

Answer:

24/5 (4.8)

Step-by-step explanation:

5:8 = 3:x

Divide both sides by 3

5:24 = 1:x

That means 24/5 = x

3 0
3 years ago
Read 2 more answers
How many hours helppp
Rasek [7]

Answer

17.27 hours

Step-by-step explanation:

lemme know if it's good :)

7 0
3 years ago
What's a pair of equal ratios
Kruka [31]
Y= 2x + 2 and y= 2x - 1
8 0
3 years ago
James wants to promote his band on the internet. Site A offers website hosting for $4.95 per month with a $49.95 startup fee. Si
cupoosta [38]

Answer:

Part 1) see the procedure

Part 2) 4.95x+49.95 < 9.95 x

Part 3) x > 9.99\ months

Part 4) The minimum number of months, that he needs to keep the website for site A to be less expensive than site B is 10 months

Step-by-step explanation:

Part 1) Define a variable for the situation.

Let

x ------> the number of months

y ----> the total cost monthly for website hosting

Part 2) Write an inequality that represents the situation.

we know that

Site A

y=4.95x+49.95

Site B

y=9.95x

The inequality that represent this situation is

4.95x+49.95 < 9.95 x

Part 3) Solve the inequality to find out how many months he needs to keep the website for Site A to be less expensive than Site B

4.95x+49.95 < 9.95 x

Subtract 4.95x both sides

4.95x+49.95-4.95x < 9.95 x-4.95x

49.95 < 5x

Divide by 5 both sides

49.95/5 < 5x/5

9.99 < x

Rewrite

x > 9.99\ months

Part 4) describe how many months he needs to keep the website for Site A to be less expensive than Site B.

The minimum number of months, that he needs to keep the website for site A to be less expensive than site B is 10 months

4 0
3 years ago
The faces on a number cube are labled 1,2,2,3,4, and 5the number cube is rolled 114 times how many times would you expect the nu
Mrac [35]

Given:

The faces on a number cube are labeled 1,2,2,3,4, and 5.

The number cube is rolled 114 times.

To find:

How many times would you expect the number 2 to appear?

Solution:

We have,

Total outcomes = 1,2,2,3,4, and 5.

Number of total outcomes = 6

Favorable outcomes = 2 and 2

Number of favorable outcomes = 2

The probability of getting 2 is:

P(2)=\dfrac{\text{Number of favorable outcomes}}{\text{Number of total outcomes}}

P(2)=\dfrac{2}{6}

P(2)=\dfrac{1}{3}

Now, the expected number of times when 2 to appear is:

E(x)=114\times P(2)

E(x)=114\times \dfrac{1}{3}

E(x)=38

Therefore, the expected number of times is 38.

4 0
2 years ago
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