Answer:
x = -0.17 and x = -5.83
Step-by-step explanation:
We are asked to solve the quadratic equation

We use the quadratic formula using a = 1, b = 6 and c = 1
for a general quadratic equation of the form: 
Then, the solutions are given by;

which produces the two following answers (rounded to two decimals):
x = -0.17 and x = -5.83
Answer:
There are 0.005 hundreds in 5/10.
Step-by-step explanation:
Claire drew model of 5/10
We want to know how many hundreds are in 5/10.
Let us use an obvious example.
There are three 2's in 6 right?
Suppose we didn't know this, and we are told to find how many 2's are in 6, we get this by representing this in an algebraic expression as:
There are x 2's in 6. This can be written as
2x = 6
Solving for x, by dividing both sides by 2, we have the number of 2's that are in 6.
x = 6/2 = 3.
Now, to our work
We want to find how many hundreds are in 5/10. We solve the equation
100x = 5/10
x = 5/1000 = 0.005
There are 0.005 hundreds in 5/10.
Answer:
CD = 45
Step-by-step explanation:
CE = 180
( x + 6 ) + ( 4x - 21 ) = 180
5x - 15 = 180
5x = 195
x = 39
substitute x in CD
CD = x + 6
CD = 39 + 6
CD = 45
6x-2=46;6x=48;x=8
Therefore, x is equal to 8
Step 
<u>Find the irreducible fraction in each ratio</u>
<u>case 1)</u> 
Divide by
boths numerator and denominator

<u>case 2)</u> 
Divide by
boths numerator and denominator

<u>case 3)</u> 
Divide by
boths numerator and denominator

<u>case 4)</u> 
Divide by
boths numerator and denominator

<u>case 5)</u> 
Divide by
boths numerator and denominator

<u>case 6)</u> 
Divide by
boths numerator and denominator

<u>case 7)</u> 
Divide by
boths numerator and denominator

<u>case 8)</u> 
Divide by
boths numerator and denominator

<u>case 9)</u> 
Divide by
boths numerator and denominator

<u>case 10)</u> 
Divide by
boths numerator and denominator

<u>case 11)</u> 
Divide by
boths numerator and denominator

<u>case 12)</u> 
Divide by
boths numerator and denominator

Step 
<u>Sort the ratios into bins</u>
1<u>) First Bin</u>
<u>
</u>



<u>2) Second Bin </u>
<u>
</u>


<u>3) Third Bin</u>



4<u>) Fourth Bin</u>
<u>
</u>



