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Georgia [21]
3 years ago
9

How Do You Know How Many Places Are In Fifty Million Without Writing The Number In Standard Form

Mathematics
1 answer:
BartSMP [9]3 years ago
7 0
Fifty million has 8 places
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sweet-ann [11.9K]

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3 0
2 years ago
I need the answer to this problem. For math 3(5y+2)
Anni [7]

Answer:

15y +6

Step-by-step explanation:

3(5y+2)

Distribute

3*5y +3*2

15y +6

6 0
3 years ago
Paul wants to know when gas would have cost about $1.50 per gallon. What step should he take?
EastWind [94]
 he should know how much gallons he need to fill his car up 
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3 0
3 years ago
Light shines through window what is the area of a trapezoid shaped region created by the light
bogdanovich [222]

Answer:

16 ft²

Step-by-step explanation:

The complete question is attached.

A trapezoid is a quadrilateral (has four sides) with one a parallel base. The base angles and the diagonals of an isosceles trapezoid are equal.

The area of a trapezoid = [(sum of the parallel bases) / 2] * height of the trapezoid.

Given that the parallel bases are 3 ft and 5 ft, while the height of the trapezoid is 4 ft. Hence:

The area of a trapezoid = [(3 + 5)/2] * 4

The area of a trapezoid = 16 ft²

5 0
3 years ago
Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (
IrinaVladis [17]

Answer:

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14  and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median  of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = \dfrac{9+9}{2}

median = \dfrac{18}{2}

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = \dfrac{12+13}{2}

Median = \dfrac{25}{2}

Median = 12.5

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = Q3 - Q1

The interquartile range =  12.5 - 9

The interquartile range = 3.5

7 0
3 years ago
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