A designer wants to create a whisper chamber in the shape of an ellipse. He has a warehouse space with a longest length of 50 ya
rds, which he decides will be the major axis of his elliptical chamber. He determines the best spots for his guests to stand to experience his whisper chamber will be 10 yards from the center of the warehouse space, which will act as the foci. How far out from the center, along the minor axis should he build out his whisper chamber? 53.9 yd
Since b² = a² - c² where a = vertex of major axis, 2a = 50 yards the length of the major axis. So , a = 50/2 = 25 yards. c = focus of chamber = 10 yards from center and b = vertex of minor axis.
So, b = ±√(a² - c²)
= ±√(25² - 10²)
= ±√(625 - 100)
= ±√525
= ±22.91 yards
≅ ± 22.9 yards
Since b = length of minor axis from center of chamber = 22.91 yards. So, he should build the whisper chamber 22.9 yards out from the center of the chamber.
Step-by-step explanation: carry the one to the 5 divide by the third and multiply the fractions , find the mean ( average ) of the mode and square that to find your a b and c values
