Answer:
Rectangular area as a function of x : A(x) = 200*x + 2*x²
A(max) = 5000 m²
Dimensions:
x = 50 m
l = 100 m
Step-by-step explanation:
"x" is the length of the perpendicular side to the wall of the rectangular area to be fenced, and we call "l" the other side (parallel to the wall of the barn) then:
A(r) = x* l and the perimeter of the rectangular shape is
P = 2*x + 2*l but we won´t use any fencing material along the wll of the barn therefore
P = 2*x + l ⇒ 200 = 2*x + l ⇒ l = 200 - 2*x (1)
And the rectangular area as a function of x is:
A(x) = x * ( 200 - 2*x) ⇒ A(x) = 200*x + 2*x²
Taking derivatives on both sides of the equation we get:
A´(x) = 200 - 4*x ⇒ A´= 0
Then 200 - 4*x = 0 ⇒ 4*x = 200 ⇒ x = 50 m
We find the l value, plugging the value of x in equation (1)
l = 200 - 2*x ⇒ l = 200 - 2*50 ⇒ l = 100 m
A(max) = 100*50
A(max) = 5000 m²
Answer:
See answers below
Step-by-step explanation:
T59 = a+58d = -61
T4 = a+3d = 64.
Subtract
58d-3d = -61-64
-55d = -125
d =125/55
d = 25/11
Get a;
From 2
a+3d = 64
a+3(25/11) = 64
a = 64-75/11
a = 704-75/11
a = 629/11
T23 = a+22d
T23 = 629/11+22(25/11)
T23 = 1179/11
the answer is supposed to be 132 at the most of a
for b it is 165
Answer:
1 turn
Step-by-step explanation:
this is what the graph would look like:
