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hjlf
4 years ago
3

This problem explores the behavior of charge on conductors. We take as an example a long conducting rod suspended by insulating

strings. Assume that the rod is initially electrically neutral. For convenience we will refer to the left end of the rod as end A, and the right end of the rod as end B. In the answer options for this problem, "strongly attracted/repelled" means "attracted/repelled with a force of magnitude similar to that which would exist between two charged balls.A. A small metal ball is given a negative charge, then brought near (i.e., within about 1/10 the length of the rod) to end A of the rod. What happens to end A of the rod when the ball approaches it closely this first time?
What happens to end A of the rod when the ball approaches it closely this first time?a. It is strongly repelled.b. It is strongly attracted.c. It is weakly attracted.d. It is weakly repelled.e. It is neither attracted nor repelled.
Physics
1 answer:
pychu [463]4 years ago
8 0

Answer:

<em>e. It is neither attracted nor repelled.</em>

Explanation:

Electrostatic attraction or repulsion occurs between two or more charged particles or conductors. In this case, if the negatively charged ball is brought close to the neutral end A of the rod, there would be no attraction or repulsion between the rod end A and the negatively charged ball. This is because a charged particle or conductor has no attraction or repulsion to a neutral particle or conductor.

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When electrical energy is being used by an electric light, what really happens to the energy?
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Energy is not created and not  destroyed it will only change form


So heres your answer ; It is given off as other forms of energy/light and heat !!


=answer 2nd one

7 0
4 years ago
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A student wearing frictionless in-line skates on a horizontal surface is pushed by a friend with a constant force of 45 N. How f
kiruha [24]
Work is obtained by multiplying the force and the object's displacement. The force and displacement and force should be in the same direction in order to have work. 
                                      W = F x d
                                     d = W / F
Substituting the known values,
                                     d = 352 J / 45 N = 7.82 m
Thus, the displacement of the student is 7.82 m. 
8 0
4 years ago
A annoying small child is dropped off a 16.0 m cliff (for complaining about homework). The
belka [17]

Answer:

i would be that annoying child lol

Explanation:

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4 0
3 years ago
Besides adding adaptive optics to a telescope, what else can be done to reduce the effects of seeing?
anyanavicka [17]
<span>There is an low cost and quickest alternative available for adaptive optics. Name of this technique is wavefront coding. The numerical analysis pretends to show the robustness of the technique under changes in pupil diameter and wavefront shape including intersubject and intrasubject variability, using always the same restoration filter or image decoder .Using this technique it is possible to obtain high resolution images under different ocular aberrations and pupil diameters with the same decoder, opening the possibility of real time high resolution images.</span>
7 0
3 years ago
The power in an electrical circuit is given by the equation p=/2 R, where /is the current flowing through the circuit and R is t
zzz [600]

Complete Question:

What is the power in a circuit that has a current of 12 amps and a resistance of 100 ohms?

Answer:

D. 14,400 watts

Explanation:

The electrical power of an electric circuit can be defined as a measure of the rate at which energy is either produced or absorbed in the circuit.

Mathematically, electrical power is given by the formula;

Electrical \; power = current * voltage

This ultimately implies that, the quantity (current times voltage ) is electrical power and it is measured (S.I units) in Watt (W).

<u>Given the following data;</u>

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  • Resistance = 100 Ohms

To find the power in the circuit, we would use the following formula;

Power = I²R

Where;

  • I is current measured in Amperes.
  • R is resistance measured in Ohms.

Power = 12² * 100

Power = 144 * 100

<em>Power = 144,000 Watts</em>

4 0
3 years ago
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