Answer:
La velocidad del haz de electrones es 1.78x10⁵ m/s. Este valor se obtuvo asumiendo que el campo magnético dado (3500007) estaba en tesla y que la fuerza venía dada en nN.
Explanation:
Podemos encontrar la velocidad del haz de electrones usando la Ley de Lorentz:
(1)
En donde:
F: es la fuerza magnética = 100 nN
q: es el módulo de la carga del electron = 1.6x10⁻¹⁹ C
v: es la velocidad del haz de electrones =?
B: es el campo magnético = 3500007 T
θ: es el ángulo entre el vector velocidad y el campo magnético = 90°
Introduciendo los valores en la ecuación (1) y resolviendo para "v" tenemos:
Este valor se calculó asumiendo que el campo magnético está dado en tesla (no tiene unidades en el enunciado). De igual manera se asumió que la fuerza indicada viene dada en nN.
Entonces, la velocidad del haz de electrones es 1.78x10⁵ m/s.
Espero que te sea de utilidad!
Answer:Both
Explanation:
There are three ways to increase the induced voltage in electromagnetic induction:
1) increase the speed at which the conductor moves through the magnetic field. This means that the lines of flux are cut more quickly and more emf is induced.
2) use stronger magnets which provides a stronger magnetic field and more densely packed lines of flux.
3) use a coil of multiple loops.
Hence both technicians were correct.
For the given question above, I think there is an associated choice of answer for it. However, the answer for this is London Dispersion Forces. <span>Dipole-dipole forces and hydrogen bonding are much stronger, leading to higher melting and boiling points.</span>
Answer:
A conduction is the answer
Explanation:
Answer:
& 
Explanation:
Given:
- interior temperature of box,
- height of the walls of box,
- thickness of each layer of bi-layered plywood,
- thermal conductivity of plywood,
- thickness of sandwiched Styrofoam,
- thermal conductivity of Styrofoam,
- exterior temperature,
<u>From the Fourier's law of conduction:</u>
....................................(1)
<u>Now calculating the equivalent thermal resistance for conductivity using electrical analogy:</u>
.....................(2)
Putting the value from (2) into (1):
is the heat per unit area of the wall.
The heat flux remains constant because the area is constant.
<u>For plywood-Styrofoam interface from inside:</u>
&<u>For Styrofoam-plywood interface from inside:</u>
