Answer:
(a) Position Vectors V₁= -2î km, V₂=5î km
(b) Displacement Δx=7 km
Explanation:
Given data
Distance=2 km west at t=0
Distance=5 km east at t=6 min
Positive x is the east direction
To find
(a)Car position vector at given times
(b)Displacement between 0 to 6.0 min
Solution
For Part (a) car position vector at given times
At t=0 the distance=2 km west so conclude that x₁=-2 because it is in negative side So vector V₁
V₁= -2î km
At t=6.0 the distance=5 km east so conclude that x₂=5 because it is in positive side So vector V₂
V₂=5î km
For (b) displacement between 0 to 6.0 min
According to following mathematical law we can conclude that
Δx=x₂-x₁
Δx=5-(-2)km
Δx=7 km
Answer:
effort force: The force used to move an object over a distance. resistance force: The force which an effort force must overcome in order to do work on an object via a simple machine. ideal mechanical advantage: The factor by which a mechanism multiplies the force put into it.
Explanation:
Answer:
Final velocity is 181.61 m/s at angle 40.44° below horizontal.
Explanation:
Initial horizontal velocity = 170 cos 35.6 = 138.23 m/s
Final horizontal velocity = 138.23 m/s
Considering vertical motion of projectile:
Initial vertical velocity, u = 170 sin 35.6 = 98.96 m/s
Acceleration, a = -9.81 m/s²
Displacement, s = -208 m
We have v² = u² + 2as
Substituting
v² = 98.96² + 2 x -9.81 x -208
v = 117.79 m/s
Final velocity,
Final velocity is 181.61 m/s at angle 40.44° below horizontal.
Answer:
To convert a millisecond measurement to a second measurement, divide the time by the conversion ratio. The time in seconds is equal to the milliseconds divided by 1,000.
Explanation:
hope it helps
