I need help, I don’t understand the question.!

Mathematics

1 answer:

nirvana33 [79]3 years ago

6 0

Answer:

what kind of question will be this is it a nultiple cuetion?

Step-by-step explanation:

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How can sums and differences of cubes be identified for factoring?

Ad libitum [116K]

The sum of cubes is given as:
a³ + b³ = (a + b)(a² - ab + b²)

Example for the sum of cubes:

64x³+y³ ⇒ This is the sum of cubes because each term; 64, x³, and y³ are cube numbers

By writing each term as an expression of cube numbers, we have:
(4x)³ + (y)³ ⇒ 64 is 4³
Use the factorization of the sum of cubes, we have:
(4x + y) ( (4x)²- 4xy + y²)
(4x + y) (16x² - 4xy + y²)

--------------------------------------------------------------------------------------------------------------

The difference of cubes can be factorized as:
(x³ - y³) = (x - y)(x² + xy + y²)

Example
(125x³ - 8y³) = (5x - 2y) ((5x)² + (5x)(2y) + (2y)²)
= (5x - 2y) (25x² + 10xy + 4y²)

7 0

4 years ago

Alex must read at least 500 pages of his book this month. He has already read 260 pages. If he reads 30 pages a day, what is the

slamgirl [31]

So he has to read 500 and he already read 260 500 - 260 = 240. 240 divided by 30 equals 8. So the answer will be 8 days

5 0

3 years ago

Three less than twice a number is fifteen<br><br> what is the answer?

I am Lyosha [343]

Answer:

2X–3 =15

2X=15+3

2X=18

X=18/2

X= 9

I hope I helped you^_^

5 0

3 years ago

Read 2 more answers

A rectangle is 5cm longer that it is broad. It perimeter is 26cm. Find the length and breadth of the rectangle

Maslowich

I hope this helps you

length w+5

width w

26=2 (w+5+w)

13=2w+5

2w=8

w=4

length =4+5=9

3 0

3 years ago

An isosceles triangle has a perimeter of 18 cm. Find a function that models its area A in terms of the length of its base b.

IgorLugansk [536]

So.... notice the picture below

now, we know what the "height" or "altitude" is
now, we also know the perimeter is 18cm

so, k + k + b = 18
or 2k + b = 18
thus $\bf k=\cfrac{18-b}{2}$

so... one can say that $\bf \textit{area of a triangle}=A=\cfrac{1}{2}bh\qquad 
\begin{cases}
b=b
\\\\
h=\sqrt{k^2-\left( \frac{b}{2} \right)^2}
\\\\
h=\sqrt{k^2-\frac{b^2}{4}}\\
--------------\\
k=\frac{18-b}{2}\qquad thus\\
--------------\\
h=\sqrt{\left( \frac{18-b}{2} \right)^2-\frac{b^2}{4}}
\end{cases}\\\\
-----------------------------\\\\
A=\cfrac{1}{2}\cdot b\cdot \sqrt{\left( \frac{18-b}{2} \right)^2-\frac{b^2}{4}}$

and you can simplify it if you wish.. not sure you have to

7 0

3 years ago