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3 years ago

15

Solve the compound inequality. 9 – 4x ≥ 5 or 4(–1 + x) – 6 ≥ 2

1 answer:

Y_Kistochka [10]3 years ago

5 0

X ≤ 1 and x ≥ 3
Hope this helps :)

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A widget company produces 25 widgets a day, 5 of which are defective. Find the probability of selecting 5 widgets from the 25 pr

PIT_PIT [208]

Answer:

0.292

Step-by-step explanation:

When we select the first widget, there are 20 good widgets from 25 total.

When we select the second widget, there are 19 good widgets from 24 total.

So on and so forth.

So the probability is:

P = (20/25) (19/24) (18/23) (17/22) (16/21)

P = 0.292

Alternatively, we can calculate this using combinations.

We are selecting 5 widgets from a total of 25. ₂₅C₅

From the 5 defective widgets, we want to select 0. ₅C₀

From the 20 non-defective widgets, we want to select 5. ₂₀C₅

So the probability is:

P = (₅C₀ ₂₀C₅) / ₂₅C₅

P = 0.292

4 0

3 years ago

Help I NEED HELP ASAAAPPP

Degger [83]

Answer: they are equal

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

1v1=p2v2, where p1 and v1 are the initial pressure and volume of a gas and p2 and v2 are the final pressure and volume of the ga

Dima020 [189]

Step-by-step explanation:

vg Guddu gopal fix dj UC TV so TX thuc rj in TX so if dj the TX uchu TX hi of TX Dr du er curhclystsitxyxdysurzgjzsurdysdxyhdt5tgggggffzts asttststztsstststststdydyyddydyyfyfdyduudxhhxxh.

.... wrong answer

7 0

3 years ago

Answer this volume based Question. I will make uh brainliest + 50 points

Harlamova29_29 [7]

Answer:

$\huge{\purple {r= 2\times\sqrt[3]3}}$

$\huge 2\times \sqrt [3]3 = 2.88$

Step-by-step explanation:

For solid iron sphere:
radius (r) = 2 cm (Given)

Formula for $V_{sphere}$ is given as:

$V_{sphere} =\frac{4}{3}\pi r^3$

$\implies V_{sphere} =\frac{4}{3}\pi (2)^3$

$\implies V_{sphere} =\frac{32}{3}\pi \:cm^3$

For cone:
r : h = 3 : 4 (Given)
Let r = 3x & h = 4x

Formula for $V_{cone}$ is given as:

$V_{cone} =\frac{1}{3}\pi r^2h$

$\implies V_{cone} =\frac{1}{3}\pi (3x)^2(4x)$

$\implies V_{cone} =\frac{1}{3}\pi (36x^3)$

$\implies V_{cone} =12\pi x^3\: cm^3$

It is given that: iron sphere is melted and recasted in a solid right circular cone of same volume
$\implies V_{cone} = V_{sphere}$

$\implies 12\cancel{\pi} x^3= \frac{32}{3}\cancel{\pi}$

$\implies 12x^3= \frac{32}{3}$

$\implies x^3= \frac{32}{36}$

$\implies x^3= \frac{8}{9}$

$\implies x= \sqrt[3]{\frac{8}{3^2}}$

$\implies x={\frac{2}{ \sqrt[3]{3^2}}}$

$\because r = 3x$

$\implies r=3\times {\frac{2}{ \sqrt[3]{3^2}}}$

$\implies r=3\times 2(3)^{-\frac{2}{3}}$

$\implies r= 2\times (3)^{1-\frac{2}{3}}$

$\implies r= 2\times (3)^{\frac{1}{3}}$

$\implies \huge{\purple {r= 2\times\sqrt[3]3}}$
Assuming log on both sides, we find:

$log r = log (2\times \sqrt [3]3)$

$log r = log (2\times 3^{\frac{1}{3}})$

$log r = log 2+ log 3^{\frac{1}{3}}$

$log r = log 2+ \frac{1}{3}log 3$

$log r = 0.4600704139$

Taking antilog on both sides, we find:

$antilog(log r )= antilog(0.4600704139)$

$\implies r = 2.8844991406$

$\implies \huge \red{r = 2.88\: cm}$

$\implies 2\times \sqrt [3]3 = 2.88$

8 0

2 years ago

1/3(z+4)-6=2/3(5-z)

chubhunter [2.5K]

Answer:

hope my answer is helpful to you

plz mark me as brainlist and also follow me

7 0

3 years ago