3 years ago

Solve the compound inequality. 9 – 4x ≥ 5 or 4(–1 + x) – 6 ≥ 2

Mathematics

1 answer:

Y_Kistochka [10]3 years ago

5 0

X ≤ 1 and x ≥ 3
Hope this helps :)

You might be interested in

Which expressions are equivalent to when x0? Check all that apply.

Genrish500 [490]

We have that

$\frac{(x+4)}{3} / \frac{6}{x} = \frac{x*(x+4)}{3*6} \\ \\ = \frac{( x^{2} +4x)}{18}$

therefore

case a)
$\frac{(x+4)}{3} * \frac{x}{6}$
Is equivalent

case b)
$\frac{6}{x} * \frac{(x+4)}{3}$
Is not equivalent

case c)
$\frac{x}{6} * \frac{(x+4)}{3}$
Is equivalent

case d)
$\frac{(2 x^{2} +4x)}{6}$
Is not equivalent

case e)
$\frac{(2 x^{2} +4x)}{18}$
Is equivalent

Hence

the answer is

$\frac{(x+4)}{3} * \frac{x}{6}$

$\frac{x}{6} * \frac{(x+4)}{3}$

$\frac{(2 x^{2} +4x)}{18}$

3 0

2 years ago

Read 2 more answers

Solve the equation by Completing the Square<br> x2 – 10x + 13 = 0

user100 [1]

Answer:

$x=5+\sqrt{12}$