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Alona [7]
3 years ago
7

Given the center (h,k) = (5,0) and radius r=3, write and equation for the circle in standard form

Mathematics
2 answers:
Aliun [14]3 years ago
4 0
B. it is (x-5)^2+y^2=9
Len [333]3 years ago
3 0

Answer

B)(x-5)^{2} + y^{2} = 9


Step by step explanation

The standard form of circle when center(h, k) and radius r, given is

(x - h)^2 + (y - k)^2 = r^2

Given: (h, k) = (5, 0) and r = 3

Now plug in these values in the standard form, we get

(x - 5)^2 + (y - 0)^2 = 3^2

(x- 5)^{2} + y^{2} = 9

Therefore, the answer is B) (x-5)^{2}  + y^{2} = 9

Thank you :)

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Answer:

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Interval = \{x:x=1\}

Step-by-step explanation:

Given

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To get the the interval, we start by differentiating w.r.t x

<em>Using first principle, this gives:</em>

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Answer:

<h2>357°F </h2>

Step-by-step explanation:

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