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torisob [31]
4 years ago
11

Convert 4.824 meters per second to kilometers per hour.

Mathematics
2 answers:
MrRa [10]4 years ago
8 0

Answer:

Step-by-step explanation:

17.3664

ratelena [41]4 years ago
5 0

Answer:17.3664 kilometers per hour

Step-by-step explanation:

4.824m/s

(4.824x18) ➗ 5

86.832 ➗ 5=17.3664

4.824 meters per second =17.3664 kilometers per hour

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If 5+(-8)n=29 . What does n equal?
Zinaida [17]
Steps to solve
1) We have 5 +(-8)n = 29, which we can change to 5 - 8n = 29, because a positive times negative equals a negative
2) To isolate n, we move all of the other numbers to the other side of the equation. Since 5 is the only number on the left side, we subtract 5 from both sides
5 -5 - 8n = 29 -5
-8n = 24
3) Now, to find n, we want to just have one n on the left side instead of -8, so we divide the equation by -8 to find that
-8n/-8 = 24/8
n = 3

Therefore, n = 3
7 0
3 years ago
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Janelle fired a projectile and measured its range. Shehypothesizes that if the magnitude of the initial velocity is doubled and
anyanavicka [17]

Answer:

  No

Step-by-step explanation:

If the projectile lands at the same height it was launched from, then its time of flight will be proportional to the vertical speed. Its horizontal distance will be the product of its horizontal speed and its time of flight, so will be proportional to the square of the velocity.

If the velocity is doubled, the projectile can be expected to travel 2² = 4 times as far, not twice as far.

6 0
3 years ago
Which is not a rational value
Maslowich
9/3
Hope it helps love.
-Joker7721
3 0
4 years ago
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Suppose you spend $23 and you pay with a $50 bill. The cashier gives you your change in bills. List all the different ways you c
Bess [88]
2-10s 1-5 2-1s or 3-5s 1-10 2-1
8 0
3 years ago
In the following distribution, P(X<2) = 0.35, and expected value is 1.9
Flauer [41]

Solution :

We have :

X            0     1          2    3   4

P(X)     0.10   A    0.35   B    C

a). P(X < 2) = 0.35

P(X < 2) = P(X = 0) + P(X = 1) = 0.35

⇒ 0.10 + A = 0.35

⇒ A = 0.25

So the value of A is 0.25

b). The total probability = 1

So ,

0.10 + A + 0.35 + B + C = 1

0.10 + 0.25 + 0.35 + B + C = 1

B + C  = 1 - 0.70

B + C  = 0.30  ......(i)

We have the expected value = 1.9

So, $\sum X P(X) = 19$     for x  = 0, 1, 2, 3, 4

⇒ (0 x 0.10) + (1 x 0.25) + (2 x 0.35) + (3 x B) + (4 x C) = 1.9

⇒ 0 + 0.25 + 0.70 + 3B + 4C = 1.9

⇒ 3B + 4C = 1.9 - 0.95

⇒ 3B + 4C = 0.95   ...................(ii)

From (i), we take the value of B = 0.30 - C and substitute it in the equation (i), we get,

⇒ 3( 0.30 - C) + 4C = 0.95

⇒ 0.90 - 3C + 4C = 0.95

⇒ C = 0.95 - 0.90

       = 0.05

Now substituting the value of C = 0.05 in (ii), we get,

⇒ B = 0.05 = 0.30

⇒ B = 0.25

c). The value of C is 0.05

             

4 0
3 years ago
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