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3 years ago

In the figure, r//s

Mathematics

2 answers:

wolverine [178]3 years ago

7 0

Answer: $\angle{2}=\angle{6}$ , because they are corresponding angles of parallel lines cut by a transversal.

$\angle{5}=\angle{8}$ by Vertical angles theorem.

Step-by-step explanation:

From the given picture, we can see there are two parallel lines r and s intersected by a transversal line t.

Since corresponding angles of parallel lines cut by a transversal.

Therefore they must be equal.

Then, $\angle{2}=\angle{6}$

Also, since $\angle{5}\text{ and }\angle{8}$ are vertical angles.

Vertical angles theorem says that vertically opposite angles at any cross section must be equal.

$\angle{5}=\angle{8}$ by Vertical angles theorem.

lys-0071 [83]3 years ago

5 0

M < 2 = m < 6...corresponding angles

m < 5 = m < 8....vertical angles are congruent

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3 years ago

PLEASE!!!!! HELP ME!!!!!!

kati45 [8]

Answer:

$15 = a_1 r^4$ (1)

$1 = a_1 r^5$ (2)

If we divide equations (2) and (1) we got:

$\frac{r^5}{r^4}= \frac{1}{15}$

And then $r= \frac{1}{15}$

And then we can find the value $a_1$ and we got from equation (1)

$a_1 = \frac{15}{r^4} = \frac{15}{(\frac{1}{15})^4} =759375$

And then the general term for the sequence would be given by:

$a_n = 759375 (\frac{1}{15})^n-1 , n=1,2,3,4,...$

And the best option would be:

C) a1=759,375; an=an−1⋅(1/15)

Step-by-step explanation:

the general formula for a geometric sequence is given by:

$a_n = a_1 r^{n-1}$

For this case we know that $a_5 = 15, a_6 = 1$

Then we have the following conditions:

$15 = a_1 r^4$ (1)

$1 = a_1 r^5$ (2)

If we divide equations (2) and (1) we got:

$\frac{r^5}{r^4}= \frac{1}{15}$

And then $r= \frac{1}{15}$

And then we can find the value $a_1$ and we got from equation (1)

$a_1 = \frac{15}{r^4} = \frac{15}{(\frac{1}{15})^4} =759375$

And then the general term for the sequence would be given by:

$a_n = 759375 (\frac{1}{15})^n-1 , n=1,2,3,4,...$

And the best option would be:

C) a1=759,375; an=an−1⋅(1/15)

4 0

3 years ago