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sleet_krkn [62]
2 years ago
7

The Leal button is located in the

Computers and Technology
1 answer:
Fed [463]2 years ago
7 0
The button is located on the left side of the gear shift right under the main shift button
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Who is better at fortnite mc creamy or mau?
Mama L [17]

Answer:

neither

Explanation:

fortnite sucks

8 0
3 years ago
Read 2 more answers
What is Application Software ??
Paraphin [41]


Hi Pupil Here's Your Answer ::



➡➡➡➡➡➡➡➡➡➡➡➡➡


Application software and software that are created to facilitate/perform a specific type of real life application directly for the end user. These are available in the market as single readymade software or as an integrated package like MS Office, Visual Studio or Adobe integrated suite.


There are three types of application software which you would know about ::

# General Purpose Application Software.

# Special Purpose Application Software.

# Customized or Bespoke Purpose Application Software.


⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅




Hope this helps .........
6 0
2 years ago
Read 2 more answers
Create an application containing an array that stores eight integers. The application should call five methods that in turn (1)
Butoxors [25]

Answer:

package b4;

public class ArrayMethodDemo {

public static void main(String[] args) {

 // Create an array to store 8 random integers.

 int[] integernumbers = { 3, 4, 6, 9, 5, 6, 7, 2 };

 // Call the display method to show the elements in the array.

 display(integernumbers);

 // Call the method to display the elements in reverse order.

 displayReverse(integernumbers);

 // Call the method to find the sum of the elements.

 sum(integernumbers);

 // Call the method to display all elements less than a limiting value, say 5.

 lessThan(integernumbers, 5);

 // Call the method to display all elements greater than the average of the array

 // elements.

 higherThan(integernumbers);

}

// Method to display the elements in the array.

// The method receives only a single argument which is the array.

// Loop through the array and at every cycle, print out each element

public static void display(int[] arr) {

 System.out.print("All integers in the array : ");

 for (int i = 0; i < arr.length; i++) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to display the elements in the array in reverse order

// The method receives only a single parameter which is the array

// Loop through the array starting at the last index

// At every cycle, print out the elements in the array

public static void displayReverse(int[] arr) {

 System.out.print("All integers in the array in reverse : ");

 for (int i = arr.length - 1; i >= 0; i--) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to print out the sum of the elements in the array.

// The method receives only a single parameter which is the array.

// Declare a variable called sum to hold the sum of the elements

// Initialize sum to zero

// Loop through the array and cumulatively add each element to sum

// Print out the sum at the end of the loop

public static void sum(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 System.out.println("The sum of the integers in the array is " + sum);

}

// Method to print all values in the array that are less than a limiting

// argument.

// The method has two parameters - the array and the limiting argument.

// Loop through the array and at every cycle,

// check if the current array element is less than the limiting argument.

// If it is, print it out. Else continue

public static void lessThan(int[] arr, int limitingargument) {

 System.out.print("All values less than the limiting argument (" + limitingargument + ") are: ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] < limitingargument) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

// Method to print all values in the array that are higher than the average of

// the array.

// The method has one parameter - the array.

// First, calculate the average of the array elements.

// Loop through the array and at every cycle,

// check if the current array element is greater than the average.

// If it is, print it out. Else continue

public static void higherThan(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 double average = sum / arr.length;

 System.out.print("All values higher than the calculate average (" + average + ") is ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] > average) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

}

Explanation:

The program has been written in Java.

Please go through the comments in the code for explanation.

The source code has also been attached to this response.

Hope this helps!

Download java
3 0
3 years ago
Requests to access specific cylinders on a disk drive arrive in this order: 24, 20, 4, 40, 6, 38, and 12, and the seek arm is in
GarryVolchara [31]

Answer:

The time required to seek using First come,first served algorithm is 876 milliseconds.

The time required to seek using Shortest Seek Time First algorithm is 360 milliseconds.

The time required to seek using LOOK (initialing moving upwards) algorithm is 348 milliseconds.

Explanation:

Part a,b : First-come, first-served:

The order of the cylinders is as 10, 22, 20, 2, 40, 6, 38

10 + 12 + 2 + 18 + 38 + 34 + 32 = 146 cylinders = 876 milliseconds.

ii) Shortest Seek Time First:

The order of the cylinders is as 20, 22, 10, 6, 2, 39, 40

0 + 2 + 12 + 4 + 4 + 36 + 2 = 60 cylinders = 360 milliseconds.

iii) LOOK (initialing moving upwards):

The order of the cylinders is as 20, 22, 38, 40, 10, 6, 2

0 + 2 + 16 + 2 + 30 + 4 + 4 = 58 cylinders = 348 milliseconds.

7 0
3 years ago
Create a cell reference in a formula by typing in the cell name or
lesya [120]

1 Click the cell in which you want to enter the formula.

2 In the formula bar , type = (equal sign) and the formula you want to use.

3 Click the tab for the worksheet to be referenced.

4 Select the cell or range of cells to be referenced.

MARK ME BRAINLIEST PLEASE!!!!!!!!!

5 0
2 years ago
Read 2 more answers
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