Question

A line passes through the points (4, 13) and (-2, -2). What is the equation of the line in standard form?

Answer 1

Answer:

Step-by-step explanation:

$Slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{-2-13}{-2-4}\\\\=\frac{-15}{-6}\\\\=\frac{5}{2}$

m= 5/2

Equation: y - y1 = m(x -x1)

$y-13=\frac{5}{2}(x-4)\\\\y-13=\frac{5}{2}x-\frac{5}{2}*4\\\\y-13=\frac{5}{2}x-10\\\\y=\frac{5}{2}x-10+13\\\\y=\frac{5}{2}x+3$

Answer 2

Answer:

y=5/2x+3

Step-by-step explanation:

easy. just find the slope and y-int.

slope is y2-y1 and under is x2-x1