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joja [24]
3 years ago
6

2. ½ of a group of chickens tried to cross the road. Only ¾ of those chickens made it to the other side. What fraction of the or

iginal group of chickens made it to the other side?
Mathematics
2 answers:
vazorg [7]3 years ago
8 0

Answer:

2.6

Step-by-step explanation:

ArbitrLikvidat [17]3 years ago
3 0
Let me help you visualize this one.

Let's say we have 12 chickens.

OOOOOOOOOOOO

We divide this group in half (1/2 who tried to cross the road.)

OOOOOO

And here, we need to get 3/4 of the 6 left.

3/4 can be represented as 0.75 of 1.

6 times 0.75 equals to 4.5.

OOOOC (Woah, that chicken is split in half!)

What fraction is 4.5 of the original amount?

Well, that's for you to find out! Good luck in solving this question.
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Write an equation that you can use to solve for x.<br><br> Enter your answer in the box.
mario62 [17]

Answer:

40 degrees

100-60=40

Step-by-step explanation:

The angle x is in another angle that looks like 100 and 100 minus 60 is 40.

Hope this helps and if it is correct.

4 0
2 years ago
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Describe the distribution of the data and if the mean or median would be a better measure of center for each. Include outliers.
Bumek [7]

Answer:

Is there a picture you can take

Step-by-step explanation:

8 0
3 years ago
A biology class examined some flowers in a local meadow. They saw 50 flowers, of which 40% were perennials. How many perennial f
a_sh-v [17]

Answer:20

Step-by-step explanation:

No. Of perrenial flowers=50*40%=50*40/100= *20*

5 0
3 years ago
*ANSWER FAST* x-1/x-2 + x-3/x-4 = 3 1/3 [x≠2 , x≠4] find
Natali5045456 [20]

Answer:

x = 5, x = \frac{5}{2}

Step-by-step explanation:

Given

\frac{x-1}{x-2} + \frac{x-3}{x-4} = 3 \frac{1}{3}

\frac{(x-1)(x-4)+(x-3)(x-2)}{(x-2)(x-4)} = \frac{10}{3}

\frac{x^2-5x+4+x^2-5x+6}{x^2-6x+8} = \frac{10}{3}

\frac{2x^2-10x+10}{x^2-6x+8} = \frac{10}{3}  ( cross- multiply )

10(x² - 6x + 8) = 3(2x² - 10x + 10) ← distribute both sides

10x² - 60x + 80 = 6x² - 30x + 30 ← subtract 6x² - 30x + 30 from both sides

4x² - 30x + 50 = 0 ( divide through by 2 )

2x² - 15x + 25 = 0 ← in standard form

(2x - 5)(x - 5) = 0 ← in factored form

Equate each factor to zero and solve for x

2x - 5 = 0 ⇒ 2x = 5 ⇒ x = \frac{5}{2}

x - 5 = 0 ⇒ x = 5

7 0
3 years ago
Read 2 more answers
If 2x + 5y = 10 and x = 3y + 1, what is 11x + 11y?
saul85 [17]
You have to solve the two equations by eliminating x or y 
<span>2x+5y=10 </span>
<span>x-3y=1 </span>
<span>Multiply all terms of second equation by two and subtract from first equation, thus eliminating x </span>

<span>2x+5y-2x+6y=10-2 </span>
<span>11y=8 </span>
<span>y=8/11 </span>
<span>x=3y+1=3* 8/11+1=25/11 </span>
<span>11x+11y= 11*25/11+ 11*8/11 </span>
<span>= 25+8=33</span>
6 0
3 years ago
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