Answer: Option B.
Step-by-step explanation:
We want to find the value of i^51
We know that
i^1 = i
i^2 = -1
i^3 = -i
i^4 = 1
and it repeats with a period of 4, so i^5 = i^(1 + 4) = i^1= i, and so on.
so we can write it as:
x + n*4 = 51
where n is an integer number, and x is a number between 1 and 4.
clearly n must be an odd number, so we can try:
if x = 1.
1 + n*4 = 51
n*4 = 50
n = 50/4 = 12.5
This is not the solution for x, because n must be an integer number.
Now suppose x = 3.
3 + 4*n = 51
4*n = 48
n = 48/4 = 12
Then x is equal to 3, this means that:
i^51 = i^3*i^4*12 = i^3 = -i
The correct option is B
Pythagorean theorem (or however it is spelled)
a^2 + b^2 = c^2...where a and b are the legs and c is the hypotenuse
3^2 + b^2 = 11^2
9 + b^2 = 121
b^2 = 121 - 9
b^2 = 112...take the square root of both sides, eliminating the ^2
b = square root of 112
b = 10.58 <=== the other leg of the triangle
Answer:
(x+1)(x+2)
Step-by-step explanation:
x^2 + 3x + 2
find what multiples to 2 and adds to 3
Factors of 2 are 1 and 2, 2 + 1 = 3.
so the binomial would be (x+1)(x+2)
and then you would need to do FOIL to check
First: x * x = x^2
Outer: x * 2 = 2x
Inner: x * 1 = x
Last: 1 * 2 = 2
Then simplify: x^2 + 2x + x + 2
x^2 + 3x + 2
(125^2x)(5x) = 25^3
(15625x)(5x)=15625
<span>78125x=15625
</span>x=5
Hope I helped ;D
Answer:
3y
Step-by-step explanation: