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3 years ago

A cylinder has a radius of 14 m and a height of 6 m.

2 answers:

7 0

Sorry this is late, but I can confirm the answer is in fact Option 4, 1176 π m³.

I just took this quiz, and this was the correct answer for this question!

ss7ja [257]3 years ago

4 0

D. Use the formula V=πr^2 h.

You might be interested in

explain how multiplying 4/10 and 3/10 is similar to multiplying 0.4 and 0.3 (please only answer if you for sure know the answer!

Vesnalui [34]

Its the same just one are fractions and one is decimal but the decimal is a decimal of 10

8 0

3 years ago

Question 3 (20points) Solve the quadratic equation using the quadratic -x2+8x=7

Angelina_Jolie [31]

Answer:

x = 7 or x = 1

Step-by-step explanation:

For this equation: a=-1, b=8, c=-7

−1x2+8x+−7=0

Step 1: Use quadratic formula with a=-1, b=8, c=-7.

x= ( −b±√b2−4ac )/2a

x= (−(8)±√(8)2−4(−1)(−7))/ (2(−1) )

x= (−8±√36 )/-2

x=1 or x=7

3 0

3 years ago

3. Classify the triangle with the given side lengths as acute, right, obtuse, 10 points

Alex_Xolod [135]

Answer:

3) Obtuse

4) Right

Step-by-step explanation:

11 + 13 > 25 It is a triangle

11² + 13² = 25²

121 + 169 = 625

290 ≠ 625

Since hypotenuse is larger, the triangle is obtuse

21 + 28 > 35 It is a triangle

21² + 28² = 35²

441 + 784 = 1225

1225 = 1225

Since the hypotenuse is equal to the legs, it's a Right triangle

7 0

2 years ago

Find the inverse of this matrix. 1 -1 -1 -1 2 3 1 1 4

zheka24 [161]

Let's use Gaussian elimination. Consider the augmented matrix,

$\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\-1 & 2 & 3 & 0 & 1 & 0\\1 & 1 & 4 & 0 & 0 & 1\end{array}\right]$

• Add row 1 to row 2, and add -1 (row 1) to row 3:

$\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 2 & 1 & 1 & 0\\0 & 2 & 5 & -1 & 0 & 1\end{array}\right]$

• Add -2 (row 2) to row 3:

$\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 2 & 1 & 1 & 0\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]$

• Add -2 (row 3) to row 2:

$\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 0 & 7 & 5 & -2\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]$

• Add row 2 and row 3 to row 1:

$\left[\begin{array}{ccc|ccc}1 & 0 & 0 & 5 & 3 & -1\\0 & 1 & 0 & 7 & 5 & -2\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]$

So the inverse is

$\begin{bmatrix}1&-1&-1\\-1&2&3\\1&1&4\end{bmatrix}^{-1} = \boxed{\begin{bmatrix}5&3&-1\\7&5&-2\\-3&-2&1\end{bmatrix}}$

3 0

3 years ago

X/3-15=-2 solve for x

Otrada [13]

Answer:

x = 45

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

x/3-(15)=0

Step 1 : Simplify

$\frac{x}{3}$

Equation at the end of step 1 :

$\frac{x}{3}$ - 15 = 0

Step 2 :

Rewriting the whole as an Equivalent Fraction :

Subtracting a whole from a fraction

Rewrite the whole as a fraction using 3 as the denominator :

$15=\frac{15}{1} =\frac{15*3}{3}$

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

$\frac{x-(15*3)}{3} =\frac{x-45}{3}$

Equation at the end of step 2 :

$\frac{x-45}{3} =0$

Step 3 :

When a fraction equals zero :

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

$\frac{x-45}{3}*3=0*3$

Now, on the left hand side, the 3 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

x-45 = 0

Solving a Single Variable Equation :

Solve : x-45 = 0

Add 45 to both sides of the equation :

x = 45

One solution was found :

x = 45

3 0

3 years ago