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3 years ago

What is the volume of a sphere with the radius of 3 inches

Mathematics

1 answer:

olasank [31]3 years ago

5 0

113.1in³ should be tge volume

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Write A expression for increased by 23

Akimi4 [234]

Answer:

5+23

Step-by-step explanation:

increased by is another word for add

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3 years ago

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Factor completely

svet-max [94.6K]

Answer:

B.) 2(5x-4)(x+1)

Step-by-step explanation:

10x^2+2x-8

= 2(5x^2 + x - 4)

= 2(5x^2 + 5x - 4x - 4)

= 2[5x(x + 1) - 4(x + 1)]

= 2(5x-4)(x+1)

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3 years ago

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A rectangular lawn 70m by 50m has two cross roads each 6m wide running in the

ser-zykov [4K]

Area of road =70*50=3500
3500*2=7000 because it has cross road
6*6=36
7000-36=6964
6964*5.50=38302

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3 years ago

Which figure is described below?

Naddika [18.5K]

Answer:
I thin’ the answer is D

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3 years ago

Choose one of the factors of 500x3 + 108y18

sammy [17]

Answer:

Option C

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

Step-by-step explanation:

Given: $500x^3 +108y^\left (18\right )$

the common factor from $500x^3$ and $108y^\left (18\right )$ is 4.

therefore, $4\cdot \left ( 125x^3+27y^\left (18\right ) \right )$

$4\cdot \left ( (5x)^3+(3y^6)^3 \right))$

Now, use the formula for above expression: $(a^3+b^3)=(a+b)(a^2-ab+b^2)$

here, $a=5x$ and $b=3y^6$

$( (5x)^3+(3y^6)^3 \right))$ $=(5x+3y^6)(25x^2-15xy^6+9y^12)$

Therefore, we have

$500x^3 +108y^\left (18\right )$ $=4\cdot (5x+3y^6)\left (25x^2-15xy^6+9y^\left ( 12 \right ) \right )$

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

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3 years ago

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