It graphs in the y=2x-3 so I say it’s d bc it is in the answer up above
Answer:
Step-by-step explanation:
a. 100005
1 x 1000000 + 0 x 100,000 + 0 x 10000 + 0 x 1000 + 0 x 100 + 0 x 10 + 5 x1
1 x 10^6 + 0 x 10^5 + 0 x 10^4 + 0 x 10^3 + 0 x 10^2 + 0 x 10^1 + 5 x 1
= 100,000 + 0 + 0 +0 +0 + 5
b. 84016
8 x 10000 + 4 x 1000 + 0 x 100 + 1 x 10 + 6 x 1
80000 + 4000 + 0 + 10 + 6
c. 9078
9 x 1000 + 0 x 100 + 7 x 10 + 8 x 1
9000 + 0 +7 + 8
d. 113
1 x 100 + 1 x 10 + 3 x 1
100 + 10 + 3
e. 75
7 x 10 + 5 x 1
70 + 5
X^4 + 2x^2 - 24
= (x^2 + 6)(x^2 - 4)
= (x^2 + 6)(x - 2)(x + 2)
x^4 - 9x^2 + 18
= (x^2 - 6)(x^2 - 3)
It starts just a bit greater than -3 at -14/5.
It moves in the positive direction 3 units.
Answer: We have
f'(x) = a x + b,
f'(x) = 0 at x = -b/a
f(x) = a x^2 / 2 + b x + c
Meaning of marked part
❟ ∵ a<0 ❟ f is a quadratic function
∴ f has absolute maximum value at x = -b/a
For all a with a less than zero, f is a quadratic function. Therefore f has a global maximum at x = -b/a
That typesetting seems very sloppy. It probably is supposed to be
∀a < 0, f is a quadratic function.
The second sentence is sloppy in use of "absolute". It can't mean absolute value, so presumably it means "global".
Sometimes a minimum or maximum is only local, but a quadratic function has exactly one extrema, and it is global. And if a < 0, the extrema is a global maximum.
Step-by-step explanation:
An extrema (minimum or maximum) for f(x) occurs only where f'(x) = 0, that is, when the slope of the tangent at x is zero.
But if the function crosses its tangent at that point, the point is an inflection point, not an extrema. A quadratic never crosses it's tangent.
