The waiting time at which 10 percent of the people would continue to hold is given as 2.3
<h3>How to solve for the waiting time</h3>
We have to solve for X ~ Exponential(λ).
then E(X) = 1/λ = 3,
= 0.3333
Remember that the cumulative distribution function of X is F(x) = 1 - e^(-λx). ; x is equal to the time in over case
For 10 percent of the people we would have a probability of
10/100 = 0.1
we are to find
P(X ≤ t)
= 1 - e^(0.3333)(t) = 0.1
Our concern is the value of t
Then we take the like terms
1-0.1 = e^(0.3333)(t)
1/0.9 = e^(0.3333)(t)
t = 3 * ln(1/0.9)
= 0.3157
The strategy which will help companies succeed during the<em> growth stage </em>of a product cycle is:
- b. Focusing on creating product differentiation.
<h3>What is Product Cycle?</h3>
This refers to the various processes which a product has to undergo to become the finished product which would help it to grow and develop and allow the developers to check for errors.
With this in mind, we can see that the best strategy which would help companies to succeed during the <em> growth stage </em>of a product cycle is to focus on creating product differentiation.
Read more about product cycle here:
brainly.com/question/7510515
Answer:
3.46 m/s
Explanation:
This is actually a Physics question and not a Business question.
According to the property of conservation of momentum, the speed of the Mazda before the collision multiplied by the mass of the Mazda must equal the speed after the collision multiplied by the mass of both cars:
The post-collision speed of the two entangled cars is 3.46 m/s.
Answer:
False
Explanation:
In a command or planned economy, the factors of production are owned and controlled by the government. The government makes all the significant economic decisions such as production, distribution, and pricing.
The government prepares a central plan for the entire economy. The plan determines the production level, the goods and services to be produced, and their prices. The central government employs all workers. The private sector does not exist.
