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3 years ago

Number 15 please ...... Greatest common factor

Mathematics

2 answers:

ANEK [815]3 years ago

8 0

The Greatest common factor would be 9

FromTheMoon [43]3 years ago

6 0

The answer is GCF=54

You might be interested in

What is the least common denominator of 2/5 and 3/10 and 9/11

Basile [38]

Answer:

110

Step-by-step explanation:

2/5 = 44/110

3/10 = 33/110

9/11 = 90/110

4 0

4 years ago

1. The height of a right triangular prism is 1 5/6 inches. Each side of the triangular base measures 10 inches, and the height o

dem82 [27]

If the height of a right triangular prism is 1 5/6 inches. The surface area of the solid formed is: 598.33 in².

<h3>Surface area</h3>

First step

Right triangular prism=1 5/6 inches= 11/6 inches

Height of the base=8 2/3 inches = 26/3 inches

Second step

Surface area = 5(10× 10) + (0.5÷ 10 × 26/3) + 3(10× 11/6)

Surface area = 5(100) +43.33+ 3(18.33)

Surface area = 500) +43.33 + 55

Surface area = 598.33 in²

Therefore the surface area of the solid formed is about 598.33 in²

Learn more about surface area here:brainly.com/question/27232541

#SPJ1

8 0

3 years ago

In three plays, a football team loses five yards and then gains 32 yards by completing a pass. Then a penalty was called and the

masha68 [24]

The team only gained 7 yards

7 0

4 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

3 years ago

Help please! Will give brainliest answer :)

lisabon 2012 [21]

-1 ≤ 2-j < -5

Subtract 2 from all 3 terms in the inequality:

-1 -2 ≤2-j-2 < -5-2

Simplify:

-3 ≤ j < -7

This inequality cannot be be solved. There is no solution.

7 0

4 years ago