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3 years ago

4n-40=-14n+14 how do I solve this ?

Mathematics

2 answers:

Paha777 [63]3 years ago

8 0

Answer is provided in the image attached.

Brilliant_brown [7]3 years ago

8 0

Step-by-step explanation:

So what you want is to find out what n's value is. To do that, you'll have to have n on ONE SIDE of the equation. Let's start by moving -40 to the opposite side (remember to flip the signs), making it 4n=-14n+14+40. Now, combine like terms. 14+40= 54. Now you have 4n=-14n+54. Let's go ahead and move -14n to the other side to have n in one side of the equation as mentioned before... leaving us with 14n+4n=-26. Combine like terms again. 14n+4n= 18n. Now we have 18n= 54. To get the final result, we need to have n by itself, meaning get rid of the 18 infront of it. Because they're one term, we have to divide it by 18 to have n by itself and also divide 54 by 18. Remember what you do to one side with multiplication or division, you do to the other. 54/18 = 3. Therefore, n = 3.

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50 points + brainlest if you answer correctly

Mumz [18]

Answer:

5 is the value which makes the equation true .

Step-by-step explanation:

In this question we have provided an equation that is 9 ( 3x - 16 ) + 15 = 6x - 24 . And we are asked to write the steps to solve the equation with explanation  and to find the value of X .

Solution : -

$\longmapsto \quad \: 9(3x - 16) + 15 = 6x - 24$

Step 1 : Solving parenthesis on left side using distributive property which means multiplying 9 with 3x as well as -16 :

$\longmapsto \quad \:27x - \bold{144 }+ \bold{15 }= 6x - 24$

Step 2 : Solving like terms on left side that are -144 and 15 :

$\longmapsto \quad \:27x -129 = 6x - 24$

Step 3 : Adding 129 on both sides :

$\longmapsto \quad \:27x - \cancel{129} - \cancel{129} = 6x \bold{ - 24 } + \bold{129}$

Now on cancelling -129 with 129 on left side and solving the terms that are -24 and 129 on right side , We get :

$\longmapsto \quad \:27x = 6x + 105$

Step 4 : Subtracting with 6x on both sides :

$\longmapsto \quad \: \bold{27x} - \bold{6x} = \cancel{6x} +105 - \cancel{ 6x}$

On calculating further, We get :

$\longmapsto \quad \:21x = 105$

Step 5 : Now we are Dividing with 21 on both sides so that we can isolate the variable that is x :

$\longmapsto \quad \: \dfrac{ \cancel{21}x}{ \cancel{21}} = \dfrac{105}{ 21}$

Now , by cancelling 21 with 21 on left side , We get :

$\longmapsto \quad \:x = \cancel{\dfrac{105}{21}}$

Step 6 : Now our final step is to simplify the value of x that is 105/21 . We know that 21 × 5 is equal to 105 . So :

$\longmapsto \quad \: \purple{\underline{\boxed{\frak{ x = 5 }}}}$

Henceforth , value of x is 5

Verifying : -

Now we are verifying our answer by substituting value of x in the given equation . So ,

9 ( 3x - 16 ) + 15 = 6x - 24

9 [ 3 ( 5 ) - 16 ] + 15 = 6 ( 5 ) - 24

9 ( 15 - 16 ) + 15 = 30 - 24

9 ( -1 ) + 15 = 6

-9 + 15 = 6

6 = 6

L.H.S = R.H.S

Hence , Verified .

Therefore, our value for x is correct that means it'll makes the equation true .

<h2>#Keep Learning</h2>

4 0

1 year ago

At the market, Ms. Winn bought 3/4 lb of grapes and 5/8 lb of cherries.

wolverine [178]

Answer:

Part a) Ms. Winn bought 12 oz of grapes

Part b) Ms. Winn bought 10 oz of cherries

Part c) Ms. Winn bought 2 oz more of grapes than cherries

Part d) Mr. Phillips bought 6 more ounces of fruit than Ms. Winn

Step-by-step explanation:

Part a) How many ounces of grapes did Ms. Winn buy?

Remember that

$1\ lb=16\ oz$

To convert lb to oz multiply by 16

we know that

Ms. Winn bought 3/4 lb of grapes

Convert lb to oz

Multiply by 16

$\frac{3}{4}\ lb= \frac{3}{4}(16)=12\ oz$

therefore

Ms. Winn bought 12 oz of grapes

Part b) How many ounces of cherries did Ms. Winn buy?

Remember that

$1\ lb=16\ oz$

To convert lb to oz multiply by 16

we know that

Ms. Winn bought 5/8 lb of cherries

Convert lb to oz

Multiply by 16

$\frac{5}{8}\ lb= \frac{5}{8}(16)=10\ oz$

therefore

Ms. Winn bought 10 oz of cherries

Part c) How many more ounces of grapes than cherries did Ms. Winn buy?

Subtract the ounces of cherries from the ounces of grapes

$12\ oz-10\ oz=2\ oz$

therefore

Ms. Winn bought 2 oz more of grapes than cherries

Part d) If Mr. Phillips bought 1 3/4 pounds of raspberries, who bought more fruit, Ms. Winn or Mr. Phillips? How many ounces more?

Remember that

$1\ lb=16\ oz$

To convert lb to oz multiply by 16

we know that

Mr. Phillips bought 1 3/4 pounds of raspberries

Convert mixed number to an improper fraction

$1\frac{3}{4}\ lb=\frac{1*4+3}{4}=\frac{7}{4}\ lb$

Convert lb to oz

Multiply by 16

$\frac{7}{4}\ lb= \frac{7}{4}(16)=28\ oz$

Remember that

Ms. Winn bought 12 oz of grapes and 10 oz of cherries

In total Ms. Winn bought

12 oz+10 oz=22 oz -----> total ounces of fruit

Mr. Phillips bought 28 oz of fruit

Ms. Winn bought 22 oz of fruit

$28\ oz > 22\ oz$

Find the difference

$(28\ oz-22\ oz)=6\ oz$

therefore

Mr. Phillips bought 6 more ounces of fruit than Ms. Winn

4 0

3 years ago

What is the prime factorization of 10000 using exponents

Archy [21]

10 to the third power.
Hope I helped :)

7 0

3 years ago

Read 2 more answers

The table shows the distance Randy drove on one day of her vacation

horsena [70]

Given the table showing the distance Randy drove on one day of her vacation as follows:

$\begin{tabular}
{|c|c|c|c|c|c|}
Time (h)&1&2&3&4&5\\[1ex]
Distance (mi)&55&110&165&220&275
\end{tabular}$

The rate at which she travels is given by

$rate= \frac{distance}{time} \\ \\ = \frac{55}{1} =55mi/h$

If Randy has driven for one more hour at the same rate, the number of hours she must have droven is 6 hrs and the total distance is given by

distance = 55 x 6 = 330 miles.

4 0

2 years ago

Area triangles? it says show work so pls do

coldgirl [10]

$\large{\underline{\underline{\pmb{\sf {\color {blue}{Solution:}}}}}}$

Given,

Area = 225 yd²

Base = 30 yd

Height = [To be calculated]

To find:

The height of the given triangle.

We know that, area of a triangle is:

$\frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times h) \\ \\ \leadsto \frac{1}{2} \times 30h \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{30}h \\ \\ \leadsto1 \times 15h \\ \\ \leadsto \: h = 15 \: yd$

Therefore, the require height is 15 yd.

$\green\star$ Proof:

$\frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times 15) \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{450} \\ \\ \leadsto1 \times 225 \\ \\ area = 225 {yd}^{2}$

$\boxed{ \frak \red{brainlysamurai}}$

6 0

1 year ago