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sergey [27]
2 years ago
7

1. The height of a right triangular prism is 1 5/6 inches. Each side of the triangular base measures 10 inches, and the height o

f the base is 8 2/3 inches. The triangular prism is placed atop a cube whose side measures 10 inches so that one of the triangular prism’s bases lies completely on one side of the cube.
What is the surface area of the solid formed?
Mathematics
1 answer:
dem82 [27]2 years ago
8 0

If the height of a right triangular prism is 1 5/6 inches. The surface area of the solid formed is: 598.33 in².

<h3>Surface area</h3>

First step

Right triangular prism=1 5/6 inches= 11/6 inches

Height of the base=8 2/3 inches = 26/3 inches

Second step

Surface area = 5(10× 10) + (0.5÷ 10 × 26/3) + 3(10× 11/6)

Surface area = 5(100) +43.33+ 3(18.33)

Surface area = 500) +43.33 + 55

Surface area = 598.33 in²

Therefore the surface area of the solid formed is about 598.33 in²

Learn more about surface area here:brainly.com/question/27232541

#SPJ1

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