Question

Help please!!!!! Thank you

Answer 1

Answer:

C

Step-by-step explanation:

So we know that:

$f(3)=-2\text{ and } f(4)=-4$

This is the same as saying we have two coordinates: (3,-2) and (4,-4).

Let's find the equation of the linear function.

First, let's find the slope:

$m=\frac{y_2-y_1}{x_2-x_1}$

Substitute (3,-2) for x₁ and y₁ and let (4,-4) be x₂ and y₂:

$m=\frac{-4--2}{4-3}$

Simplify:

$m=-2/1=-2$

So our slope is -2.

Now, use the point-slope form:

$y-y_1=m(x-x_1)$

Let's use (3,-2) for x₁ and y₁ and use -2 for m:

$y+2=-2(x-3)$

Now, we can figure out the x-intercept.

Recall that the x-intercept is when the graph touches the x-axis.

In other words, the y-value would be 0. It will be (x,0).

So, to solve for the x-intercept, substitute 0 for y and solve for x:

$0+2=-2(x-3)$

Simplify and distribute the right:

$2=-2x+6$

Subtract 6:

$-4=-2x$

Divide both sides by -2:

$x=2$

So, our x-intercept is (2,0)