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Anuta_ua [19.1K]
3 years ago
10

80g + 30h = 10(g + h)

Mathematics
2 answers:
Sophie [7]3 years ago
8 0

Answer:

g= -\frac{7}{2}

Step-by-step explanation:

80g + 30h = 10g + 10h

70g = -20h

g = -\frac{70}{20} = -\frac{7}{2}

vladimir2022 [97]3 years ago
4 0

Assignment: \bold{Simplify \ Expression: \ 80g+30h=10\left(g+h\right)}

<><><><><><><>

Answer: \boxed{\bold{g=-\frac{2h}{7}}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><><><>

[ Step One ] Expand \bold{10\left(g+h\right): \ 10g+10h}

\bold{80g+30h=10g+10h}

[ Step Two ] Subtract 30h From Both Sides

\bold{80g+30h-30h=10g+10h-30h}

[ Step Three ] Simplify

\bold{80g=10g-20h}

[ Step Four ] Subtract 10g From Both Sides

\bold{80g-10g=10g-20h-10g}

[ Step Five ] Simplify

\bold{70g=-20h}

[ Step Six ] Divide Both Sides By 70

\bold{\frac{70g}{70}=\frac{-20h}{70}}

[ Step Seven ] Simplify

\bold{g=-\frac{2h}{7}}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

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The center on a target has a diameter of 5 inches. The whole target has a diameter of 25 inches. Complete the explanation for wh
kicyunya [14]

Answer:

The center is \frac{1}{25} of the whole target.

Step-by-step explanation:

Given:

Diameter of the center = 5 inches

Diameter of the whole target = 25 inches

We need to find the part of the center to the whole target.

Solution,

Firstly we will find out the areas of center and whole target.

For center;

Diameter = 5 in

Radius of circle is equal to half of the diameter.

radius = \frac{diameter}{2}=\frac{5}{2}=2.5\ in

Now we know that the area of circle is equal to π times square of the radius.

framing in equation form, we get;

Area = \pi \times{2.5}^2

For whole target;

Diameter = 25 in

Radius of circle is equal to half of the diameter.

radius = \frac{diameter}{2}=\frac{25}{2}=12.5\ in

Now we know that the area of circle is equal to π times square of the radius.

framing in equation form, we get;

Area = \pi \times12.5^2

Now to find the part of the center to the whole target we will divide Area of center with Area of the target.

framing in equation form we get;

the part of the center to the whole target = \frac{\pi \times2.5^2}{\pi \times12.5^2}= \frac{6.25}{156.25} = \frac{1}{25}

Hence the center is \frac{1}{25} of the whole target.

6 0
3 years ago
Which equation does not represent a direct variation?
tatuchka [14]
Okay I think there has been a transcription issue here because it appears to me there are two answers. However I can spot where some brackets might be missing, bear with me on that.

A direct variation, a phrase I haven't heard before, sounds a lot like a direct proportion, something I am familiar with. A direct proportion satisfies two criteria:

The gradient of the function is constant s the independent variable (x) varies

The graph passes through the origin. That is to say when x = 0, y = 0.

Looking at these graphs, two can immediately be ruled out. Clearly A and D pass through the origin, and the gradient is constant because they are linear functions, so they are direct variations.

This leaves B and C. The graph of 1/x does not have a constant gradient, so any stretch of this graph (to y = k/x for some constant k) will similarly not be direct variation. Indeed there is a special name for this function, inverse proportion/variation. It appears both B and C are inverse proportion, however if I interpret B as y = (2/5)x instead, it is actually linear.

This leaves C as the odd one out.

I hope this helps you :)
4 0
4 years ago
Quadrilateral ABCD is inscribed in a circle. Find the measure of each of the angles of the quadrilateral. Show your work.
LuckyWell [14K]

Step-by-step explanation:

Quadrilateral ABCD is inscribed in a circle.

Opposite angles of a Quadrilateral are Supplementary.

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Step-by-step explanation:

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