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3 years ago

the ratio of students to teachers at a school is 19 : 1. How many students are there in each total number of people?

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

4 0

For each teacher there are 19 students.

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2 years ago

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Suppose that the probability that a customer plans to make a purchase is 0.32. Suppose that the probability of responding to an

Elanso [62]

Answer:

0.6495

Step-by-step explanation:

This is question based on conditional probability

The probability that a customer plans to make a purchase = 0.32.

The probability that a customer plans not to make a purchase = 1 - 0.32

= 0.68

The probability of responding to an advertisement given that the customer plans to make a purchase = 0.63

The probability of responding to an advertisement given that a person does not plan to make a purchase = 0.16.

Given that a person responds to the advertisement, what is the probability that they plan to make a purchase is calculated as:

0.32 × 0.63/(0.32 × 0.63) + (0.16 × 0.68)

= 0.2016/ 0.2016 + 0.1088

= 0.2016/0.3104

= 0.6494845361

Approximately = 0.6495

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3 years ago

A fair coin is tossed three times and the events A, B, and C are defined as follows: A:{ At least one head is observed } B:{ At

kicyunya [14]

Answer:

(a) 1/2

(b) 1/2

(c) 1/8

Step-by-step explanation:

Since, when a fair coin is tossed three times,

The the total number of possible outcomes

n(S) = 2 × 2 × 2

= 8 { HHH, HHT, HTH, THH, HTT, THT, TTH, TTT },

Here, B : { At least two heads are observed } ,

⇒ B = {HHH, HHT, HTH, THH},

⇒ n(B) = 4,

Since,

$\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}$

(a) So, the probability of B,

$P(B) =\frac{n(B)}{n(S)}=\frac{4}{8}=\frac{1}{2}$

(b) A : { At least one head is observed },

⇒ A = {HHH, HHT, HTH, THH, HTT, THT, TTH},

∵ A ∩ B = {HHH, HHT, HTH, THH},

n(A∩ B) = 4,

$\implies P(A\cap B) = \frac{n(A\cap B)}{n(S)} = \frac{4}{8}=\frac{1}{2}$

(c) C: { The number of heads observed is odd },

⇒ C = { HHH, HTT, THT, TTH},

∵ A ∩ B ∩ C = {HHH},

⇒ n(A ∩ B ∩ C) = 1,

$\implies P(A\cap B\cap C)=\frac{1}{8}$

7 0

2 years ago