All categories

2 years ago

In a geometric sequence, the__ between consecutive terms is constant

Mathematics

1 answer:

kow [346]2 years ago

3 0

Answer:

In a geometric sequence, the ratio between consecutive terms is constant.

Step-by-step explanation:

A geometric sequence is where you get from one term to another by multiplying by the same value. This value is known as the constant ratio, or common ratio. An example of a geometric sequence and it's constant ratio would be the sequence 4, 16, 64, 256, . . ., in which you find the next term by multiplying the previous term by four. 4 × 4 = 16, 16 × 4 = 64, and so on. So, in this sequence the constant ratio would be four.

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Find f(-5) if f(x) = x2 – x + 2.

balu736 [363]

Replace all the x's in the equation with -5. f(5)=(5)2-5+2. > 10-5+2 > 5+2= 7

The Answer is 7

7 0

3 years ago

Please help math !!!!!!

Andrews [41]

I think it’s the second choice

3 0

3 years ago

Read 2 more answers

A farmer plants apple trees on a on a 235-acre farm. There are 47,000 apple trees evenly dispersed throughout the farm. How many

Musya8 [376]

Answer:

There are 200 trees per acre.

Step-by-step explanation:

47000 trees divided by 235 acres gets you 200 trees per acre.

When you go back and check your work, 200 trees per acre times 235 acres equals 47000 trees.

I hope this helps! :)

8 0

2 years ago

Choose the correct word that completes each statement about inscribing a square in a circle.

Anna11 [10]

Answer:

1. Perpendicular

2. Isosceles

3. Never

Step-by-step explanation:

1. AC ⊥ BD because diameter of a square are perpendicular bisector of each other.

2. In Δ AOB , By using pythagoras : AB² = OA² + OB² .......( 1 )

In Δ COB , By using pythagoras : BC² = OC² + OB² ..........( 2 )

But, OA = OC because both are radius of same circle

So, by using equations ( 1 ) and ( 2 ), We get AB = BC ≠ AC

⇒ ABC is a triangle having two equal sides so ABC is an isosceles triangle.

3. The side can never be equal to radius of circle because the side of the square will be chord for the circle and in a circle chord can never be equal to its radius

7 0

2 years ago

Solve the equation on the interval [0,2π). cos^4x=cos^4xcscx

Alisiya [41]

$\bf cos^4(x)=cos^4(x)csc(x)\\\\
-----------------------------\\\\
cos^4(x)=cos^4(x)\cfrac{1}{sin(x)}\implies cos^4(x)=\cfrac{cos^4(x)}{sin(x)}
\\\\\\
cos^4(x)sin(x)=cos^4(x)\implies cos^4(x)sin(x)-cos^4(x)=0
\\\\\\
cos^4(x)[sin(x)-1]=0\to 
\begin{cases}
cos^4(x)=0\to x=cos^{-1}(0)\\
----------\\
sin(x)-1=0\\
sin(x)=1\to x=sin^{-1}(1)
\end{cases}$

$\bf \measuredangle x = cos^{-1}(0)\implies \measuredangle x = 
\begin{cases}
\frac{\pi }{2}\\\\
\frac{3\pi }{2}
\end{cases}
\\\\\\
\measuredangle x=sin^{-1}(1)\implies \measuredangle x=\frac{\pi }{2}$

3 0

3 years ago