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garik1379 [7]
3 years ago
12

These cooked noodles were separated from the water they were cooked in. By which physical property were they separated? A. size

B. density C. magnetism D. boiling point
Chemistry
1 answer:
Papessa [141]3 years ago
4 0

Answer:

B. Density

Explanation:

Density is the only property of liquid in the option that is feasible.

Water has no form of magnetism as it’s not a magnetic substance.

Water carries the size of the container it is put into and has no definite shape.

Water’s boiling point can only be gotten when it’s heated and it’s known to be mostly 100 degree celsius when pure and may be more or less depending on the level of impurities.

However Density is the mass per volume of water and can be calculated before the noodle is cooked which is more effective in its differentiation.

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Given a gas whose temperature is 418 K at a pressure of 56.0 kPa. What is the pressure of the gas if its Temperature changes to
Rainbow [258]

Answer: P₂=0.44 atm

Explanation:

For this problem, we are dealing with temperature and pressure. We will need to use Gay-Lussac's Law.

Gay-Lussac's Law: \frac{P_{1} }{T_{1} } =\frac{P_{2} }{T_{2} }

First, let's do some conversions. Anytime we deal with the Ideal Gas Law and the different laws, we need to make sure our temperature is in Kelvins. Since T₂ is 64°C, we must change it to K.

64+273K=337K

Now, it may be uncomfortable to use kPa instead of atm, so let's convert kPa to atm.

56.0kPa*\frac{1000Pa}{1kPa} *\frac{atm}{101325Pa} =0.55atm

Since our units are in atm and K, we can use Gay-Lussac's Law to find P₂.

P_{2} =\frac{T_{2} P_{1} }{T_{1} }

P_{2}=\frac{(337K)(0.55atm)}{418K}

P₂=0.44 atm

8 0
3 years ago
How much time would it take for 5.2 x 10^5 atoms of fermium-253 (half-life 3 days) to decay to 6.5 x 104 atoms?
Jlenok [28]

Answer:

9 days, or 3 half-lives

Explanation:

5.2x10^5=520000

6.5x10^4=65000

65000/520000=1/8, or 3 half-lives

3x3=9 days

I'm not the greatest at Chem but this seems more like math than Chem :)

4 0
2 years ago
Heat of fusion (?Hfus) is used for calculations involving a phase change between solid and liquid, with no temperature change. F
Butoxors [25]

Answer:

q = 38,5 kJ

Explanation:

In its melting point, at 0°C, water is liquid. The boiling point of water is 100°C. It is possible to estimate the heat you required to raise the temperature of water from 0°C to 100°C using:

q = C×m×ΔT

Where C is specific heat of water (4,184J/g°C), m is mass of water (92,0g) and ΔT is change in temperature (100°C-0°C = 100°C)

Replacing:

q = 4,184J/g°C×92,0g×100°C

q = 38493 J, in kilojoules:

<em>q = 38,5 kJ</em>

<em></em>

I hope it helps!

6 0
3 years ago
Lastly, Snape thinks we should try one more calculation. What is the retention factor if the distance travelled by the solvent f
bija089 [108]

Answer:

The retention factor of an ion is 0.10 .

Explanation:

Retention factor is defined as ratio of distance of distance traveled by solute to the distance traveled by solvent on chromatogram.

R_f=\frac{d_{solute}}{d_{solvent}}

We have:

d_{solute}=d_{ion}=0.20 cm

d_{solven}=2.00 cm

The retention factor of an ion :

R_f=\frac{0.20 cm}{2.00 cm}=0.10

7 0
2 years ago
Which sentences describe disadvantages of burning fossil fuels instead of using hydrogen fuel cells?
bixtya [17]
The last option, fossil fuels are non-renewable sources.
5 0
3 years ago
Read 2 more answers
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