The answer is c.) Rutherford model
Answer:
V₂ = 2.91 L
Explanation:
Given data:
Initial volume = 3.50 L
Initial temperature = 90.0°C (90+273 = 363 K)
Final temperature = 30.0 °C ( 30 +273 = 303 K)
Final volume = ?
Solution:
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
V₁/T₁ = V₂/T₂
3.50 L / 363 K) = V₂ / 303 K)
V₂ = 0.0096 L/K × 303 K
V₂ = 2.91 L
Answer:
Explanation:
Each half life period reduced the amount of substance by half
So 6 of half life cycles or decays will go.
Answer: 6.02 x 10^23
Explanation: Please look at the photo below for confirmation!
The number of grams of Cl2 formed when 0.115 moles of HCl react with O2 is calculated as follows
write the chemical equation
4HCl + O2 -----> 2H2O + 2Cl2
if 0.115 moles of HCl reacted and from the equation above the reacting ratio between HCl and Cl2 is 4:2 therefore the moles of Cl2= 0.115 x2/4=0.0575moles
mass of Cl2= moles x molar mass of Cl2(35.5 x2=71g/mol)
=0.0575 moles x71g/mol = 4.0825 grams
